It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.
<u>Explanation:</u>
2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂
We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

= 337.5 g AgCl
In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.
It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.
A. I think sorry if it’s wrong
Answer:
Explanation:
1 mol of methane = 6.02 * 10^23 molecules
6.70 mol of methane = x
Cross multiply
x = 6.70 * 6.02 * 10^23
x = 4.033 * 10^23 molecules.