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Oliga [24]
3 years ago
6

Please draw the resonance structure for this compound indicating formal charges and lone pairs

Chemistry
1 answer:
ikadub [295]3 years ago
8 0

Here are the resonance contributors I found.

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How many grams of AICI: are needed to produce 150 grams of NaCl?
Anettt [7]

Answer:

18.7g

Explanation:

5 0
2 years ago
2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2
Harrizon [31]

It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.

<u>Explanation:</u>

2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂

We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}

= 337.5 g AgCl

In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.

It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.

4 0
3 years ago
Solve the following problem and round the correct number of significant
RUDIKE [14]

Answer:

4.5 + 2.34 = 6.8

Sig Figs:

2

Decimals:

1

Scientific Notation:

6.8 × 10ⁿ

Words:

six point eight

5 0
3 years ago
HELP ASAP
Bezzdna [24]
A. I think sorry if it’s wrong
5 0
3 years ago
Mole Conversion: How many molecules are there in 6.70 moles of methane, CH4 ​
raketka [301]

Answer:

Explanation:

1 mol of methane = 6.02 * 10^23 molecules

6.70 mol of methane = x

Cross multiply

x = 6.70 * 6.02 * 10^23

x = 4.033 * 10^23 molecules.

8 0
3 years ago
Read 2 more answers
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