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lozanna [386]
3 years ago
10

The length of a hallway is 30 feet greater than twice it's width

Mathematics
1 answer:
Basile [38]3 years ago
3 0
L=2w+30
If I had one of the numbers I'd be able to help more
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How to find matrics M
makkiz [27]

\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -4M=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\qquad(*) \\\\M=\left[\begin{array}{ccc}a&b\\c&d\end{array}\right]\to4M=\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]

(*)\qquad\left[\begin{array}{ccc}9&7\\-4&2\end{array}\right] -\left[\begin{array}{ccc}4a&4b\\4c&4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\\\\left[\begin{array}{ccc}9-4a&7-4b\\-4-4c&2-4d\end{array}\right]=\left[\begin{array}{ccc}-3&3\\4&-18\end{array}\right]\\.\qquad\qquad\qquad\qquad\ \ \ \Downarrow\\(_{11})\qquad9-4a=-3\ \ \ |-9\\-4a=-12\ \ \ \ |:(-4)\\a=3\\\\(_{12})\qquad7-4b=3\ \ \ \ |-7\\-4b=-4\ \ \ \ |:(-4)\\b=1

(_{21})\qquad-4-4c=4\ \ \ \ |+4\\-4c=8\ \ \ \ |:(-4)\\c=-2\\\\(_{22})\qquad2-4d=-18\ \ \ \ |-2\\-4d=-20\ \ \ \ \ |:(-4)\\d=5\\\\Answer:\ A.\ M=\left[\begin{array}{ccc}3&1\\-2&5\end{array}\right]

3 0
3 years ago
Tricky twenty four answers
mixer [17]
I’m confused on your question
7 0
3 years ago
Use y=2.5x+65 to find y when x=8 show work
harkovskaia [24]

Answer: y=85

Step-by-step explanation: Substitute all x's in the equation with 8. y=2.5(8)+65. And solve y=85

8 0
2 years ago
Read 2 more answers
The vertex of f(x) = 3x ^2+ 5x + 2 is a:<br> minimum<br> maximum<br> none of these
timama [110]

Answer:

minimum

Step-by-step explanation:

Given a quadratic in standard form f(x) = ax² + bx + c ( a ≠ 0 )

• If a > 0 then vertex is a minimum

• If a < 0 then vertex is a maximum

f(x) = 3x² + 5x + 2 ← is in standard form

with a = 3

Since a > 0 then vertex is a minimum

6 0
3 years ago
What is the distance between the point (−10, −2)(−10, −2) and the point (−4, −2)(−4, −2) ?
Gnoma [55]
In this case:  x 1 = - 10,  y 1 = - 2;
x 2 = - 4 ,  y 2 = - 2
The distance between the points :
d =  \sqrt{(x 2 - x 1 ) ^{2} + ( y 2 - y 1 ) ^{2} } = \\  =\sqrt{(-4+10) ^{2} +(-2+2) ^{2} } = \\ = \sqrt{6 ^{2}+0 ^{2}  } = \sqrt{36}= 6
Answer: d = 6
4 0
3 years ago
Read 2 more answers
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