Answer:
Calcium chloride (CaCl2) would help me eat my ice cream faster
Explanation:
Addition of salt to ice melts the lowers the freezing temperature of the ice thus melting the ice easily
Adding calcium chloride to my ice cream would help me eat it faster because the melting point of calcium chloride (772°C) is lower than that of sodium chloride (melting point is 801°C). Calcium chloride would melt my ice cream faster because of its lower melting point
Oxidizing agent is that which is reduced and the reducing agent is that which is oxidized. Reduced is when the charged is decreased and oxidized when the charge is increased.
(1) 2Na + 2H2O(l) --> 2NaOH(aq) + H2(g)
The charge of Na in the reactant is 0 and the charge of Na in the NaOH is +1. Na is oxidized. Hence, it is the reducing agent.
The charge of H in H2O is +1 while that in H2 is 0. H is reduced. Hence, it is the oxidizing agent.
(2) C(s) + O2(g) --> CO2(g)
The charge of C in the reactant side is 0 and that its charge in CO2 is +4. C is oxidized. Hence, it is the reducing agent.
The charge of O in O2 is 0 while in CO2, its charge is -2. O is reduced. Hence, it is the oxidizing agent.
(3) 2MnO⁻⁴ + SO2 + 2H2O --> 2Mn²⁺ + 5SO2⁻⁴ 4H⁺
The charge of Mn in MnO⁻⁴ is 4+ while its charge in Mn²⁺ is 2+. Mn is reduced. Hence, it is the oxidizing agent.
The charged of S in SO2 is -4 while its charge in SO₂⁻⁴ is 0. S is oxidized. Hence, it is the reducing agent.
Answer:
1/10 or 0.1
Explanation:
Quantities at which equivalence can be obtained are:
95, 96, 97, 98, 99, 100, 101, 102, 103, 104
Number of quantities = N = 10
Probability that the equivalency is obtained exactly at 100 mL can be calculated as follows:
P(X = 100) = (Number of favourable outcomes) / (Total Number of Outcomes)
P(X = 100) = 1/10
P(X = 100) = 0.1
It is C). <span>It decreases as the concentration of products increases.</span>
Explanation:
Water molecules are polar, so they form hydrogen bonds. This is a unique property of water. Water has an unique boiling point and high polarity.