A 7.45 L container holds a mixture of two gases at 15 °C. The partial pressures of gas A and gas B, respectively, are 0.364 atm
and 0.684 atm. If 0.150 mol of a third gas is added with no change in volume or temperature, what will the total pressure become?
1 answer:
Answer:
stored and active
Explanation:
both cannot be thransformed into another type of energy
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Answer:
B as all the forces cancel out
Explanation:
20-20=0
25-25=0
Answer: A
1.68 N
Explanation:
F = ma = 0.024(70.0) = 1.68 N
Answer:
Oxygen
Explanation:
One mole of atoms of oxygen has a mass of 16 g, as 16 is the atomic weight of oxygen, and contains 6.02 X 1023 atoms of oxygen.
Answer:
1.62 L
Explanation:
T= 97+273.15= 370.15
R= 0.08206 atm/mol⋅K
V= 45 L
n= 2.4 mol
P= (n⋅R⋅T)/V
= (2.4 x 0.08206 x 370.15)/(45) = 1.61997 = 1.62
Answer: C
Explanation:
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