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Arisa [49]
2 years ago
5

A 7.45 L container holds a mixture of two gases at 15 °C. The partial pressures of gas A and gas B, respectively, are 0.364 atm

and 0.684 atm. If 0.150 mol of a third gas is added with no change in volume or temperature, what will the total pressure become?
Chemistry
1 answer:
kogti [31]2 years ago
8 0

Answer:

stored and active

Explanation:

both cannot be thransformed into another type of energy

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Determine the concentration of a solution of sodium hydroxide (NaOH) using a 0.500M Potassium Hydrogen Phthalate (KHP) standard
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Answer:

0.425M NaOH assuming the volume of KHP was 25.50mL and the volume of the NaOH solution was 30.0mL

Explanation:

The KHP reacts with NaOH as follows:

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<em>Where 1 mole of KHP reacts per mole of KNaP</em>

<em />

That means, the moles of KHP added to the NaOH solution = Moles NaOH at equivalence point. With the moles of NaOH and the volume in liters we can find the molar concentration of NaOH.

<em>Assuming the volume added of KHP was 25.50mL and the solution of NaOH contains 30.0mL (0.0300L), the concentration of the NaOH is:</em>

<em />

<em>Moles KHP = Moles NaOH:</em>

25.50mL = 0.02550L * (0.500mol / L) = 0.01275 moles KHP = Moles NaOH

<em>Molarity NaOH:</em>

0.01275 moles NaOH / 0.0300L =

<h3>0.425M NaOH assuming the volume of KHP was 25.50mL and the volume of the NaOH solution was 30.0mL</h3>
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2 option

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