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Anettt [7]
3 years ago
7

Which physical property can be used to classify oxygen, helium, propane, and hydrogen as being similar?

Chemistry
1 answer:
PSYCHO15rus [73]3 years ago
4 0

Answer:

state of matter

Explanation:

Because there are three state of matter namely:liquid,solid and gas and oxygen is a gas.

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As you move across the period on the periodic table what pattern can be described about the electron configurations?
xeze [42]

Answer:

Elements in the same period have same number of electronic shell and electron is increased by one in every coming element with in same electronic shell.

Explanation:

Consider the second period of periodic table. This period consist of eight elements lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine and neon.

Electronic configuration of lithium:

Li₃ = [He] 2s¹

Electronic configuration of beryllium:

Be₄ = [He] 2s²

Electronic configuration of boron:

B₅ = [He] 2s² 2p¹

Electronic configuration of carbon:

C₆ = [He] 2s² 2p²

Electronic configuration of nitrogen:

N₇ = [He] 2s² 2p³

Electronic configuration of oxygen:

O₈ = [He] 2s² 2p⁴

Electronic configuration of fluorine:

F₉ = [He] 2s² 2p⁵

Electronic configuration of neon:

Ne₁₀ = [He] 2s² 2p⁶

All these elements present in same period having same electronic shell and number of electron increased by 1.

4 0
3 years ago
Due tonight! Please help!
olchik [2.2K]

Answer:

42.98 g/L

Explanation:

6 0
3 years ago
A compound is found to contain 42.88 % carbon and 57.12 % oxygen by weight. To answer the questions, enter the elements in the o
Ipatiy [6.2K]

Answer:

The empirical formule is CO

Explanation:

Step 1: Data given

Suppose the mass of a compound is 100 grams

Suppose the compound contains:

42.88 % C = 42.88 grams C

57.12 % O = 57.12 grams O

Molar mass C = 12.01 g/mol

Molar mass O = 16.0 g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles C = mass C / molar mass C

Moles C = 42.88 grams / 12.01 g/mol

Moles C = 3.57 moles

Moles O = 57.12 grams / 16.0 g/mol

Moles O = 3.57 moles

Step 3: Calculate the mol ratio

We divide by the smallest amount of moles

C: 3.57 moles / 3.57 moles = 1

O: 3.57 moles / 3.57 moles = 1

The empirical formule is CO

3 0
2 years ago
Calculate the mass-to-mass ratio of 25.0 g of salt in 105 g of water. Work must be shown in order to earn credit.
Sveta_85 [38]

Answer:

0.23

Explanation:

  • It is known that, the mass to mass ratio of the salt to water

= (mass of salt / mass of water)

= (25.0 g / 105.0 g)

= 0.23

  • So, the answer is 0.23

4 0
3 years ago
The trend of this graph is<br><br><br> a. Negative<br><br><br> b. Positive<br><br><br> c. Zero
Sveta_85 [38]
B. positive because y increases as x does. It it were negative y would decrease as x increases and it would be 0 if y stayed the same as x increases. 
7 0
3 years ago
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