T₁ = 27°C = 27 + 273 = 300K, V₁ = 6 L,
T₂ = 150°C = 150 + 273 = 423K, V₂ = ?,
By Charles' Law: V₁/T₁= V₂/T₂
6/300 = V₂/423
423*(6/300) = V₂
8.46 = V₂
Volume at 150°C =8.46 L.
Answer:
<u></u>
Explanation:
<u>1. Balanced molecular equation</u>

<u>2. Mole ratio</u>

<u>3. Moles of HNO₃</u>
- Number of moles = Molarity × Volume in liters
- n = 0.600M × 0.0100 liter = 0.00600 mol HNO₃
<u>4. Moles Ba(OH)₂</u>
- n = 0.700M × 0.0310 liter = 0.0217 mol
<u>5. Limiting reactant</u>
Actual ratio:

Since the ratio of the moles of HNO₃ available to the moles of Ba(OH)₂ available is less than the theoretical mole ratio, HNO₃ is the limiting reactant.
Thus, 0.006 moles of HNO₃ will react completely with 0.003 moles of Ba(OH)₂ and 0.0217 - 0.003 = 0.0187 moles will be left over.
<u>6. Final molarity of Ba(OH)₂</u>
- Molarity = number of moles / volume in liters
- Molarity = 0.0187 mol / (0.0100 + 0.0031) liter = 0.456M
I’d say most likely air, oxygen, or carbon dioxide