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Mars2501 [29]
3 years ago
5

3.. Which type of graph would be most helpful for comparing the calorie-content in a variety of

Chemistry
1 answer:
Sindrei [870]3 years ago
7 0

Answer:

d. Bar graph

Explanation:

a. Line graph  - this type of graph is best for continuous data, such as how a the sales of a particular cereal drop over time

b. Pie chart  - this is best for % data, such as looking at the % of different nutrients (carbohydrates, fats, proteins) in a cereal

C. Stem-and-leaf plot  - presents quantitative data such as the ages of people who buy a brand of cereal

d. Bar graph - this is best for plotting different numbers in distinct categories to compare them to one another  

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Answer:

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Explanation:

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3 years ago
What does a mole of iron weigh
r-ruslan [8.4K]

As the atomic mass of iron is 55.847u

We say that it is the mass of one mole of iron.

By formula it can be find by

No.of mole=mass in g/molar mass

Mass in gram = no.of mole x molar mass

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4 years ago
The radioactive atom 61/27 co emits a beta particle. write an equation showing the decay
pickupchik [31]

Answer:

\rm _{27}^{60}\text{Co} \longrightarrow \,  _{-1}^{0}\text{e} + \, _{28}^{60}\text{Ni}

Explanation:

The unbalanced nuclear equation is

\rm _{27}^{60}\text{Co} \longrightarrow \,  _{-1}^{0}\text{e} + \, ?

Let's write the question mark as a nuclear symbol.

\rm _{27}^{60}\text{Co} \longrightarrow \,  _{-1}^{0}\text{e} + \,  _{Z}^{A}\text{X}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

60 = 0 + A, so A = 60 - 0 = 60, and

27 = -1 + Z, so Z  = 27 + 1 = 28

Your nuclear equation becomes

\rm _{27}^{60}\text{Co} \longrightarrow \,  _{-1}^{0}\text{e} + \, _{28}^{60}\text{X}

Element 28 is nickel, so the balanced nuclear equation is

\rm _{27}^{60}\text{Co} \longrightarrow \,  _{-1}^{0}\text{e} + \, _{28}^{60}\text{Ni}

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3 years ago
Next to each formula, write the number of atoms of each element found in one unit of the compound
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To answer this question I would have to know the elements in the compound
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