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3 years ago

3.. Which type of graph would be most helpful for comparing the calorie-content in a variety of

Chemistry

1 answer:

Sindrei [870]3 years ago

7 0

Answer:

d. Bar graph

Explanation:

a. Line graph - this type of graph is best for continuous data, such as how a the sales of a particular cereal drop over time

b. Pie chart - this is best for % data, such as looking at the % of different nutrients (carbohydrates, fats, proteins) in a cereal

C. Stem-and-leaf plot - presents quantitative data such as the ages of people who buy a brand of cereal

d. Bar graph - this is best for plotting different numbers in distinct categories to compare them to one another

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On the pH scale, which value represents an acid?<br> A. 2<br> B. 8<br> C. 12

Zielflug [23.3K]

A) 2 is the correct answer

3 0

3 years ago

Determine the oxidation number of sodium in Na202

Olegator [25]

Answer:

Explanation:

Na₂O₂

NOTE: the oxidation number of oxygen is always –2 except in peroxides where it is –1.

Thus, we can obtain the oxidation number of sodium (Na) in Na₂O₂ as illustrated below:

Na₂O₂ = 0 (oxidation number of ground state compound is zero)

2Na + 2O = 0

O = –1

2Na + 2(–1) = 0

2Na – 2 = 0

Collect like terms

2Na = 0 + 2

2Na = 2

Divide both side by 2

Na = 2/2

Na = +1

Thus, the oxidation number of sodium (Na) in Na₂O₂ is +1

5 0

3 years ago

At a certain temperature, 0.900 mol SO 3 is placed in a 2.00 L container. 2 SO 3 ( g ) − ⇀ ↽ − 2 SO 2 ( g ) + O 2 ( g ) At equil

puteri [66]

Answer: The value of $K_c$ is 0.0057

Explanation:

Initial moles of $SO_3$ = 0.900 mole

Volume of container = 2.00 L

Initial concentration of $SO_3=\frac{moles}{volume}=\frac{0.900moles}{2.00L}=0.450M$

equilibrium concentration of $O_2=\frac{moles}{volume}=\frac{0.110mole}{2.00L}=0.055M$ [/tex]

The given balanced equilibrium reaction is,

$2SO_3(g)\rightleftharpoons 2SO_2(g)+O_2(g)$

Initial conc. 0.450 M 0 0

At eqm. conc. (0.450 -2x) M (2x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[O_2][SO_2]^2}{[SO_3]^2}$

$K_c=\frac{x\times (2x)^2}{0.450-2x)^2}$

we are given : x = 0.055

Now put all the given values in this expression, we get :

$K_c=\frac{0.055\times (2\times 0.055)^2}{0.450-2\times 0.055)^2}$

$K_c=0.0057$

Thus the value of the equilibrium constant is 0.0057

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4 years ago

What do you observe on the filter paper strip after 2 to 3 hours?

just olya [345]

It would have filtered already within the time frame of 2 to 3 hours because of the molecular injection ignited by the co2 within the strip so you would observe the UNDERSIDE OF THE PAPER and the molecular tear within it

8 0

3 years ago

A variable that is not being directly tested during an experiment should be ____. changed

Kruka [31]

Controlled because there is always going to be a control group and an experimental group so that you could see the difference in the results

7 0

4 years ago