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4 years ago

14. _______________ is the opposite of 6 on the number line.

Mathematics

2 answers:

vichka [17]4 years ago

8 0

-6 is the opposite of 6 on the number line. They are both the same distance from the center which would be 0.

cricket20 [7]4 years ago

6 0

6 is six units to the right of the 0, or zero, midpoint on an infinite number line
-6 would be six units to the left of the midpoint, so it would be the opposite

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Identify the general solution for x in this equation.<br><br> 4 - ax = 2

VLD [36.1K]

Answer:

x = $\frac{2}{a}$

Step-by-step explanation:

given

4 - ax = 2 ( isolate the term in x by subtracting 4 from both sides )

- ax = 2 - 4 = - 2 ( divide both sides by - a )

x = $\frac{-2}{-a}$ = $\frac{2}{a}$

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3 years ago

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Round the following number as indicated 106,513

Salsk061 [2.6K]

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Step-by-step explanation:

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3 years ago

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Each week, Rosario drives to an ice skating rink that is 120 miles away. The round-trip takes 2.75 hours. If he averages 55 mile

ycow [4]

Distance = rate * time

trip there, 120 = 55 *t
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thinking maybe you did not copy the problem accurately...thats pretty fast.

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4 years ago

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For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.

Anni [7]

Answer:

The reduced row-echelon form of the linear system is $\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

Interchange two rows
Multiply one row by a nonzero number
Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

$\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]$

You need to follow these steps:

Divide row 1 by 2 $\left(R_1=\frac{R_1}{2}\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]$

Subtract row 1 from row 2 $\left(R_2=R_2-R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]$

Subtract row 1 multiplied by 5 from row 3 $\left(R_3=R_3-\left(5\right)R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 1 $\left(R_1=R_1-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 3 $\left(R_3=R_3-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]$

Multiply row 2 by 2 $\left(R_2=\left(2\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]$

Divide row 3 by −19 $\left(R_3=\frac{R_3}{-19}\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]$

Subtract row 3 multiplied by 16 from row 1 $\left(R_1=R_1-\left(16\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]$

Add row 3 multiplied by 6 to row 2 $\left(R_2=R_2+\left(6\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

8 0

3 years ago

What's the answer and how do u figure out number 5 only

shusha [124]

The length of a segment knowing the coordinates of its end points:
(x₁,y₁) and (x₂,y₂) is given by the formula:

Length = √[(x₁ - x₂)² + (y₁ - y₂)²]

T(1,4) ; A(4,4) ; P(3,0)

a) TA =√[(1-4)²+(4-4)²] → TA = 3
b) AP =√[(4-3)²+(4-0)²] →AP = √17 = 1.123
c) TP =√[(1-3)²+(4-0)²] → TA = √20 = 4.472

Perimeter = TA + AP + TP = 8.60

6 0

4 years ago