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podryga [215]
2 years ago
12

What volume of oxygen gas is needed to completely combust 0.202L of butane (C4H10) gas?

Chemistry
1 answer:
saveliy_v [14]2 years ago
4 0

Answer:

look at the file :)

Explanation:

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Which element gains two electrons to fill its outermost energy level?
laiz [17]
O magnesium Mg is the answer
4 0
2 years ago
A 4.24 kg marble slab has the volume of 1564 cm3 What is the density in g/cm3
miskamm [114]

Answer:

The answer is

<h2>2.71 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

volume of marble = 1564 cm³

1 kg = 1000 g

4.24 kg = 4240 g

mass = 4240 g

The density is

density =  \frac{4240}{1564}   \\  = 2.710997442...

We have the final answer as

<h3>2.71 g/cm³</h3>

Hope this helps you

7 0
2 years ago
What period is the atom in?
lys-0071 [83]
It is in period 3
It is in group 17
It is a chlorine atom because it has 17 electrons which means the atomic number is 17
6 0
3 years ago
This question is about iron three of the raw material added to a blast furnace used to extract iron from henatite are coke hemat
IrinaVladis [17]

Answer: The fourth material that is added to the blast furnace is HOT AIR which provides OXYGEN for used for combustion of carbon (Coke).

Explanation:

Iron is the second most abundant metal found in the earth's crust after aluminium. It is not found in the free metallic state but are extracted from rocks which are rich in iron that contains other materials. These are known are iron ores and the most common iron ores are haematite ( Fe2O3).

Iron can be extracted from its ore with the used of blast furnace. The materials used for extraction of iron includes:

--> Coke

--> haematite( iron ore)

--> limestone and

--> Hot air.

The iron ore is first roasted in air so that iron(III)oxide is produced. The iron(III)oxide is then mixed with coke and limestone and heated to a very high temperature. Hot air is introduced into it from the bottom of the furnace. The coke is oxidizes the the oxygen in the hot air blast to liberate carbondioxide.

7 0
2 years ago
What is the volume of 33.25g of butane gas at 293 C and 10.934 kPa?
PSYCHO15rus [73]

Answer:

V = 240.79 L

Explanation:

Given data:

Volume of butane = ?

Temperature = 293°C

Pressure = 10.934 Kpa

Mass of butane = 33.25 g

Solution:

Number of moles of butane:

Number of moles = mass/ molar mass

Number of moles = 33.25 g/ 58.12 g/mol

Number of mole s= 0.57 mol

Now we will convert the temperature and pressure units.

293 +273 = 566 K

Pressure = 10.934/101 = 0.11 atm

Volume of butane:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

V = nRT/P

V = 0.57 mol × 0.0821 atm.L/ mol.K  ×566 K  / 0.11 atm

V = 26.49 L/0.11

V = 240.79 L

6 0
3 years ago
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