Answer:416
Step-by-step explanation: Based on the given problem above, it requires a trigonometric solution. So here it goes:
The climb distance is:200 * Sec [ArcTan [10/200]] = 10√ 401 km
and the decent distance is:300 * Sec [ArcTan [10/300]] = 10√901 km
So add the given results above with 500 km and this will be the additional distance that plane moves through the air.
The answer would be in the unit meters.
((10√401 +10√901−500)∗1000)=416 meters
Hope this is the answer that you are looking for.
Answer:
the answer is 8 by one of this question.
Most graphing calculators will do weighted averages pretty easily. It is mostly a matter of data entry.
mx = -2
my = 10
(x, y) = (mx, my)/10 = (-0.2, 1)
Answer: 8.7 x 5.28
We have to find that expression , which has an estimated product of
1.→44.7 x 2.1
2.→7.5 x 8.4
3.→8.7 x 5.28
4.→38.1 x 7.3
We will start from option 1.
→44.7 x 2.1
44.7 when estimated to nearest tenth=45
2.1, when estimated to nearest tenth=2
44.7 × 2.1=45×2=90
Option 2
7.5 x 8.4
7.5 when estimated to nearest tenth=8
8.4, when estimated to nearest tenth=8
⇒7.5 × 8.4=8×8=64
Option 3
8.7 × 5.28
8.7, when estimated to nearest tenth=9
5.28, when estimated to nearest tenth=5
⇒8.7 × 5.28=9×5=45
Option D
38.1 × 7.3
38.1 when estimated to nearest tenth=38
7.3, when estimated to nearest tenth=7
⇒38×7=266
Option C:⇒8.7 × 5.28 has an estimated product of 45
