Answer:
The probability is 
Step-by-step explanation:
We can divide the amount of favourable cases by the total amount of cases.
The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 
For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function 
with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.
Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.
We can conclude that the probability for 8 rooks not being able to capture themselves is
.360 or .306
Because 3 is in the tenths place, there is a 0, and 3+6+0= 3+6=9 the sum of all the digits. And it’s a three digit decimal.
Answer:
18
Step-by-step explanation:
8 3/4 + 9 2/8
We can simplify 2/8 by dividing the top and bottom by 2
8 3/4 + 9 1/4
Add the whole numbers
8+9 = 17
3/4 + 1/4 = 4/4 = 1
Add this to the whole numbers
17+1 = 18
Work:
A 12-pack of boxes is 4 3-pack of boxes, I found this by dividing 12 by 3.
A 24-pack of boxes is 2 12-pack of boxes, found by dividing 24 by 12.
A 24-pack of boxes is 8 3-pack of boxes, found by dividing 24 by 3 or by multiplying the two previous together (sometimes may not work)
Multiply
$1.09 × 4
That gets you to $4.36, which is less than the price of a 12-pack of boxes.
Then, multiply
$4.39 × 2
That gets you $8.78, which is less than a 24-pack of boxes.
Finally, multiply
$1.09 × 8
That gets you $8.72, which is less than a 24-pack of boxes.
Answer:
The best to buy is the 3-pack of boxes of juice, because it is cheaper when buying multiple of the 3-packs than it is to buy one or more of the 12-pack or 24-pack.
Hope this helps anyone with the question.
