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Andrej [43]
3 years ago
12

Charles Darwin,

Physics
2 answers:
Roman55 [17]3 years ago
8 0
The answer is B. Artificial Selection :)
grandymaker [24]3 years ago
3 0
The answer is B artificial selection
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NEED HELP ASAP WILL MARK BRAINLIEST.
-Dominant- [34]
G is the answer for apex vs / Chehhhh
3 0
3 years ago
Which statement about two objects having the same momentum is true?
Reil [10]

Answer:

The product of mass X velocity is the same for both

Explanation:

The momentum of a body is the product of its mass and velocity.

  Momentum  = mass x velocity

Two objects having equal momentum will have the same for the product of their mass and velocity.

  • It is amount of motion a body can produce.
7 0
3 years ago
What is the velocity of a narwhal that swims 76 kilometers North in 3 hours
tino4ka555 [31]

Answer:

<h3>25km/hr</h3>

Explanation:

Velocity is the change in displacement of a body with respect to time.

Velocity - Displacement/time

Given

displacement = 76km

Time = 3hours

Substitute the given parameters into the formula;

Velocity = 75km/3hrs

Velocity = 25km/hr

Hence the velocity of the narwhal is 25km/hr

4 0
3 years ago
Apply a force of 50N to the left describe the motion of the box
GenaCL600 [577]
When a force is applied to the box , this will cause an acceleration to the box.
(force =mass×acceleration)

So the box has a constant acceleration and a changing velocity.
4 0
3 years ago
A playground merry-go-round has a mass of 50 kg and a diameter of 4.0 m. There are 4 children who want to ride on it. They have
mixer [17]

Answer:

B) I1 = 1680 kg.m^2          I2 = 1120 kg.m^2

C) V = 0.84m/s      T = 29.92s

D) ω2 = 0.315 rad/s

Explanation:

The moment of inertia when they are standing on the edge:

I1 = 1/2*M*R^2 + (m1+m2+m3+m4)*R^2   where M is the mass of the merry-go-round.

I1 = 1680 kg.m^2

The moment of inertia when they are standing half way to the center:

I2 = 1/2*M*R^2 + (m1+m2+m3+m4)*(R/2)^2

I2 = 1120 kg.m^2

The tangencial velocity is given by:

V = ω1*R = 0.84m/s

Period of rotation:

T = 2π / ω1 = 29.92s

Assuming that there is no friction and their parents are not pushing anymore, we can use conservation of the angular momentum to calculate the new angular velocity:

I1*ω1 = I2*ω2    Solving for ω2:

ω2 = I1*ω1 / I2 = 0.315 rad/s

5 0
3 years ago
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