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Andrej [43]
3 years ago
12

Charles Darwin,

Physics
2 answers:
Roman55 [17]3 years ago
8 0
The answer is B. Artificial Selection :)
grandymaker [24]3 years ago
3 0
The answer is B artificial selection
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A 63 kg kg person starts traveling from rest down a waterslide 6.0 mm above the ground. At the bottom of the waterslide, it then
gladu [14]

Answer:

change waterslide according to question. and you are good to go. check photo for solve

5 0
3 years ago
Two Force one of 12 Newton and another 24 Newton acts at 90 degree with each other find the resultant of two force and its direc
Leona [35]

Answer:

Fr = 26.83 [N]

Explanation:

To solve this problem we must use the Pythagorean theorem, since the forces are vector quantities, that is, they have magnitude and density. Therefore the Pythagorean theorem is suitable for the solution of this problem.

F_{r}=\sqrt{(12)^{2}+(24)^{2}  } \\F_{r}=26.83[N]

3 0
3 years ago
The element Ne, neon, has ____ (number) complete shells having its ____ electrons in second _____.
KatRina [158]

Answer:

2, 8 and shell

Explanation:

Neon as atomic number 10. Since for each shell, electrons equal 2n².

When n = 1, 2n² = 2(1)² = 2

When n = 2, 2n² = 2(2)² = 8

So it fills both the first and second shell with 2 and 8 electrons respectively to achieve its stable atomic state. The rest of the 8 electrons go into the second shell because the first shell has achieved its stable dual configuration of two electrons. The next shell requires a maximum of 8 electrons to achieve stability so, the remaining electrons fill it up to achieve the stable octet configuration.

8 0
3 years ago
What is the frequency, in units of kiloHertz, of an AC waveform that has a period of 12 microseconds?
Alik [6]

Answer:

83.3 kHz

Explanation:

The frequency of a waveform is equal to the reciprocal of its period:

f=\frac{1}{T}

where

f is the frequency

T is the period

In this problem, we have

T=12 \mu s=12\cdot 10^{-6} s

so, the frequency of the waveform is

f=\frac{1}{12 \cdot 10^{-6} s}=8.33\cdot 10^4 Hz

And by converting into kiloHertz,

f=8.33\cdot 10^4 Hz=83.3 kHz

3 0
3 years ago
A very hard rubber ball (m = 0.5 kg) is falling vertically at 4 m/s just before it bounces on the floor. The ball rebounds back
saw5 [17]

Answer:

The force exerted by the floor is 80 N.

Explanation:

Given that,

Mass of ball = 0.5 kg

Velocity= 4 m/s

Time t = 0.05 s

When the ball rebounds then the kinetic energy is

K.E =\dfrac{1}{2}mv^2

Where, m = mass of ball

v = velocity of ball

Put the value into the formula

K.E=\dfrac{1}{2}\times0.5\times(4)^2

K.E = 4\ J

The average force exerted by the floor on the ball = change in kinetic energy over collision time

F = \dfrac{4}{0.05}

F=80\ N

Hence, The force exerted by the floor is 80 N.

4 0
3 years ago
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