How long does it take to shut down a nuclear reactor?.

What is the power of a circuit with voltage 12 V and current 8.0<br> A?

SVEN [57.7K]

Answer:96 W

Explanation:

3 0

3 years ago

A sailboat picks up a gust of wind and accelerates to a speed of 6m/s in 16 seconds.If the initial velocity 1 m/s,what is the ac

noname [10]

Answer:

0.3125m/s

Explanation:

3 0

3 years ago

Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference between its te

QveST [7]

Answer:

Please see attachment

Explanation:

Please see attachment

8 0

3 years ago

A rocket achieves a lift-off velocity of 500.0 m/s from rest in 30.0 seconds. Calculate the average acceleration of the rocket.

Anettt [7]

Answer:

The average acceleration is 16.6 m/s² ⇒ 1st answer

Explanation:

A rocket achieves a lift-off velocity of 500.0 m/s from rest in

30.0 seconds

The given is:

→ The initial velocity = 0

→ The final velocity = 500 meters per seconds

→ The time is 30 seconds

Acceleration is the rate of change of velocity of the rocket

→ $a=\frac{v-u}{t}$

where a is the acceleration, v is the final velocity, u is the initial velocity

and t is the time

→ u = 0 , v = 500 m/s , t = 30 s

Substitute these values in the rule

→ $a=\frac{500-0}{30}=\frac{500}{30}=16.6$ m/s²

<em>The average acceleration is 16.6 m/s²</em>

6 0

3 years ago

An armada of spaceships that is 1.60 ly long (in its rest frame) moves with speed 0.800c relative to the ground station in frame

miskamm [114]

Answer:

(a). The trip take a time is 3.61 year.

(b). The trip take a time is 3.96 year.

(c). The trip take a time is 8.73 year.

Explanation:

Given that,

Length = 1.60 ly

Speed of spaceships= 0.800c

Speed of messenger = 0.910 c

(a). We need to calculate the velocity of armada

Using formula of velocity

$v'=\dfrac{v-v_{m}}{1-\dfrac{vv_{m}}{c^2}}$

Put the value into the formula

$v'=\dfrac{0.800c-0.910c}{1-\dfrac{0.800\times0.910 c^2}{c^2}}$

$v'=\dfrac{-0.11c}{1-0.800\times0.910}$

$v'=-0.404c$

We need to calculate the length

Using formula of length

$l=l'\sqrt{1-\dfrac{v'^2}{c^2}$

Put the value into the formula

$l=1.60\sqrt{1-(-0.404)^2}$

$l=1.46\ ly$

We need to calculate the length of the trip

Using formula of time

$t=\dfrac{l}{|v'|}$

Put the value into the formula

$t=\dfrac{1.46}{0.404}$

$t=3.61\ year$

(b). If the armada's rest frame

We need to calculate the length

Using formula of length

$l=l'\sqrt{1-\dfrac{v'^2}{c^2}$

Put the value into the formula

$l=1.60\sqrt{1-(0)^2}$

$l=1.60\ ly$

Using formula of time

$t=\dfrac{l}{|v'|}$

Put the value into the formula

$t=\dfrac{1.60}{0.404}$

$t=3.96\ year$

(c). If an observer in frame S

We need to calculate the length

Using formula of length

$l=l'\sqrt{1-\dfrac{v'^2}{c^2}$

Put the value into the formula

$l=1.60\sqrt{1-(0.800)^2}$

$l=0.96\ ly$

We need to calculate the time

$t=\dfrac{0.96}{0.910-0.800}$

$t=8.73\ year$

Hence, (a). The trip take a time is 3.61 year.

(b). The trip take a time is 3.96 year.

(c). The trip take a time is 8.73 year.

8 0

3 years ago