How long does it take to shut down a nuclear reactor?.

Idaho Jo is doing physics experiments throughout the solar system. She travels to each planet and shoots a potato straight up in

Natalka [10]

Answer:

Mercury / Mars

Explanation:

For an object launched straight upward, the following SUVAT equation can be used

$v^2-u^2=-2gh$

where

v is the final velocity

u is the initial velocity

g is the acceleration of gravity (free fall acceleration) (the negative sign is due to the downward direction of gravity)

h is the maximum height reached

At the maximum height, the velocity is zero, so v = 0. Re-arranging the equation,

$h=\frac{u^2}{2g}$

So we see that for equal initial velocity (u), the maximum height reaches is inversely proportional to the acceleration of gravity. Therefore, the potato gun will reach the highest altitude in the planets with lowest acceleration of gravity, therefore Mercury and Mars (3.7 and 3.6 m/s^2).

4 0

3 years ago

Which of the following is least likely to result from seafloor spreading

Assoli18 [71]

Answer:

An reversal in the magnetic fields of the north and south pole. This would be the most logical option for me...correct me if I'm wrong.

Explanation:

New seafloor is formed when magma is forced upward toward the surface at a mid-ocean.

7 0

3 years ago

a ball is dropped and falls with an acceleration of 9.8m/s^2 downward. it hits the ground with a velocity of 49m/s downward. how

yaroslaw [1]

The answer below...........

8 0

3 years ago

Help! PROJECTILE PROBLEM: A 7500-kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.25

dsp73

Here,

height at failure, h1 = 525 m,
upward acceleration, a = 2.25 m/s^2,
velocity = v m/s,

SO, 

v^2 = 2*a*h = 2*2.25*525 = 2362.5 
Now, acceleration, g = 9.8 m/s^2,

SO, 

heigt, h1 = v^2/2g = 2362.5 / 2*9.8 = 120.54 meters 
Hence,

a) 
Total height = 525+120.54 = 645.54 meters

b)
time, for h1, t = v/g = sqrt(2362.5)/9.8 = 4.96 sec

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4 0

3 years ago

Read 2 more answers

You hang a heavy ball with a mass of 10 kg from a gold wire 2.6 m long that is 1.6 mm in diameter. You measure the stretch of th

PolarNik [594]

Answer: The Young's modulus for the wire is $6.378\times 10^{10}N/m^2$