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Luda [366]
3 years ago
14

Question 9 of 10

Mathematics
1 answer:
AlladinOne [14]3 years ago
8 0

Answer:$14,046 apexxx

Step-by-step explanation:

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Answer this, pic below.
Bad White [126]

Answer:

constant

Step-by-step explanation:

8 0
2 years ago
A 19%<br> b 26<br> c 67% <br> d 28%
Murrr4er [49]

Answer:

d= 28%

Step-by-step explanation:

4 0
3 years ago
The parent function f(x) = x3 is translated to form g(x), as shown on the graph. The translated function can be written in the f
OLEGan [10]

Answer: First option

Step-by-step explanation:

By definition, the horizontal shift depends on the value of <em>h </em>and the vertical shift depends on the value of <em>k</em><u>.</u>

f(x)=(x-h)^3 indicates that the function if shifted to the right <em>h </em> units.

f(x)=(x+h)^3 indicates that the  function if shifted to the left <em>h </em> units.

f(x)=f(x)-k indicates that the  function if shifted  down <em>k </em> units.

f(x)=f(x)+k indicates that the  function if shifted up <em>k </em> units.

Then:

If <em>h </em>is positive, the graph will shift to the right.

If <em>k </em>is negative, the graph will shift down.

 As you can see in the graph, the function is shifted 4 units to the right and 2 units down. Therefore g(x) has the form:

 g(x)=(x-4)^3-2

Where:

h=4\\k=-2

7 0
2 years ago
A rectangular swimming pool is 15 meters long, 11 1/2 meters wide, and 1 1/2 meters deep. What is its volume?
-BARSIC- [3]
258 3/4 cubic meters

Explanation:
Use this formula for volume of rectangular prism: length x width x height

In this case it would be:
15 • 11 1/2 • 1 1/2 = 258 3/4

VOLUME= 258 3/4 cubic meters

Com.ment me if u have any questions
If my answer is correct, braibliest please!
-SpaceMarsg, have a nice day :DD
3 0
3 years ago
What's the answer for 4d - 35= -3
Ket [755]

Answer:

The answer is <u>8</u>.

Step-by-step explanation:

Given:

4d - 35= -3.

Now, the solution:

4d-35=-3

Adding both sides by 35 we get:

4d=-3+35

4d=32

Dividing both sides by 4 we get:

d=8

Therefore, the answer is 8.

3 0
3 years ago
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