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Luda [366]
3 years ago
14

Question 9 of 10

Mathematics
1 answer:
AlladinOne [14]3 years ago
8 0

Answer:$14,046 apexxx

Step-by-step explanation:

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20 Points!!!!!!!!!!!!
AysviL [449]
Answer: A

Explanation: The sum of the multiplicities must be .
n
.
Starting from the left, the first zero occurs at =−3.
x
=
−3.
The graph touches the x-axis, so the multiplicity of the zero must be even. The zero of −3
−3
has multiplicity 2.
2.
The next zero occurs at =−1.
x
=
−1.
The graph looks almost linear at this point. This is a single zero of multiplicity 1.
The last zero occurs at =4.
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The graph crosses the x-axis, so the multiplicity of the zero must be odd. We know that the multiplicity is likely 3 and that the sum of the multiplicities is likely 6.
5 0
3 years ago
Determine which situations would be debits from a bank account. Select all that apply. paying an electric bill
siniylev [52]

Answer:

im not sure but i think its c

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The Center of circle (x-5)^2 + (y-13)^2=81 is (-5,-13). True or false!! thanks
Mumz [18]
False. because.....

the equation of a circle is (x-h)^2 + (y-k)^2 = r^2 and the center is (h,k) 
if the center of a circle is (-5, -13) substitute the values into the equation 
so....(x- -5)^2 + (y- -13)^2 = r^2  which is (x+5)^2 + (y+13)^2 = r^2 

in this case, because you are only asking about the center of the circle from the equation the 81 or radius of the circle doesn't matter. 
3 0
3 years ago
Use Lagrange multipliers to solve the following exercise. A home improvement contractor is painting the walls and ceiling of a r
mash [69]

Answer:

Let the width of the garden =x meter

Then length=(x+4) meter

Half perimeter =36 m

So perimeter of garden =(2×36)=72 meters

According to the question

⇒2(l+b)=72

⇒2(x+x+4)=72

⇒2x+2x+4=74⇒4x=64⇒x=16 meters

Hence,the width of the garden =16 meters

The length of the garden =(16+4)=20 meters

5 0
3 years ago
Seven less than the quotient of x and 9
bulgar [2K]
X/9 - 7 is the answer. note x/9 is in fraction form
 

8 0
3 years ago
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