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kow [346]
3 years ago
13

In this ordered pair (4, -5), which number is the ordinate?

Mathematics
1 answer:
Tasya [4]3 years ago
8 0
I think it's 10. Hope it helps. Like I am saying I am not 100% sure it is but I still hope it helps

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3 0
3 years ago
SOMEONE PLEASE HELP
laiz [17]
The best answer the question above is D.

6 0
3 years ago
Read 2 more answers
Two possible solutions of √11-2x=√x^2+4x+4 are –7 and 1. Which statement is true? A) Only x = –7 is an extraneous solution.
11111nata11111 [884]

Answer:

Option D)Neither solution is extraneous.

Step-by-step explanation:

we have

\sqrt{11-2x}=\sqrt{x^{2}+4x+4}

we know that

two possible solutions are x=-7 and x=1

<u><em>Verify each solution</em></u>

Substitute each value of x in the expression above and interpret the results

1) For x=-7

\sqrt{11-2(-7)}=\sqrt{-7^{2}+4(-7)+4}

\sqrt{25}=\sqrt{25}

5=5 ----> is true

therefore

x=-7 is not a an extraneous solution

2) For x=1

\sqrt{11-2(1)}=\sqrt{1^{2}+4(1)+4}

\sqrt{9}=\sqrt{9}

3=3 ----> is true

therefore

x=1 is not a an extraneous solution

therefore

Neither solution is extraneous

7 0
3 years ago
Read 2 more answers
A new washing machine used 3 2/4 gallons of water per full load to clean cloths. If John washed 2 2/3 loads of clothes, how many
kumpel [21]
We know that
3 2/4  -------------> is (3*4+2)/4--------> 14/4-------> 7/2
2 2/3 --------------> is (2*3+2)/3--------> 8/3

if a new washing machine used 7/2 gallons of water ------------> one full load <span>cloths
</span> X gallons of water------------------------------------------------------> 8/3 of load cloths<span>
X=(8/3)*(7/2)---------> X=56/6------->28/3 gallons of water
28/3--------> 9 1/3 gallons of water

the answer is
 </span>9 1/3 gallons of water
7 0
3 years ago
a square garden with a side of 150m has a square swimming pool in the very center with a side length of 25m calculate the area o
marta [7]

Answer: 21,875 sqm

Step-by-step explanation:

Step 1:

   Find the gross area of the garden.

   Square 150m = 22,500 sqm.

Step 2:

   Find the area of the pool.

   Square 25m = 625 sqm.

Step 3:

   Subtract the area of the pool from the gross area of the garden

   to find the net area of the garden.

   22,500 - 625 = 21,875 sqm.

Warning:

   Do not subtract the side length of the swimming pool from the side length

   of the garden before squaring.

7 0
3 years ago
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