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3 years ago

What is the ratio for 3 feet to 42 inches in simplest form

Mathematics

1 answer:

Natali [406]3 years ago

5 0

Answer:

3:3.5

Step-by-step explanation:

3 feet :42 inches

42 inches=3.5 feet

3 feet:3.5 feet

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I need help with this... 4 more than some number d. and 3 is less than X. and the others :(

Greeley [361]

2) C: 4+d

3) A: x-3

4) C: 5(1-f)

I know that this is a few weeks late...

but hope this helps!

3 0

3 years ago

Khloe invested $11,000 in an account paying an interest rate of 4.8% compounded continuously. Assuming no deposits or withdrawal

Furkat [3]

Answer:

24,880

Step-by-step explanation:

A= where P is the initial amount, r is the intrest rate as a decimal fraction, and t is the time in years. Here we have:

A= 11,000e(0.048x17) = 24,875.80

round and you get 24,880

i hope this helps

3 0

2 years ago

Write a list of steps that are needed to find the measure of angle B if angle A is 72 and angle C is 113 ( the figure is a trian

Nuetrik [128]

Triangle has 3 angles, A, B, C. The total interior angle of a triangle is 180.
180 = A + B + C
180 = 72 + B + 113
180 = B + 185
B = 180 - 185
B = -5

This only proves that the figure is not a triangle because angle B is negative.

5 0

3 years ago

When you find the surface area of a cube, you ________ the length of the cube and multiply by 6.

garik1379 [7]

Answer:

A-square

Step-by-step explanation:

The formula for the surface area of a cube is:

SA = 6a²

where a is the length of the cube

7 0

2 years ago

Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that

RUDIKE [14]

The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)= $f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........$

Where the terms in f prime $f^{1}$ (a) represent the derivatives of x valued at a.

For the given function.f(x)=8/x and a=-4.

So,f(a)=f(-4)=8/(-4)=-2.

$f^{1}$ (a)= $f^{1}$ (-4)=-8/( $-4)^{2}$

=-8/16

=-1/2

The series of f(x) is as under:

f(x)=f(-4)+ $f^{1}(-4)(x+4)/1!+ f^{11}(-4)(x+4)^{2}/2!.............$

$=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+ 24/(-4)^{3} (-4)(x+4)^{2}/2!.............$

=-2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Learn more about taylor series at brainly.com/question/23334489

#SPJ4

3 0

9 months ago