The price of a particular stock is represented by the linear equation y=-0.91x+103.47

Mathematics

2 answers:

Mila [183]3 years ago

8 0

Answer:

so A if any one asks

Step-by-step explanation:

Mama L [17]3 years ago

4 0

To find the price of the stock after 12 weeks, you would have to plug in 12 to x

That would make your equation: y = -0.91(12) + 103.47

Then, you solve:

-0.91(12) would be -10.12

Your equation will now look like this:

y = - 10.12 + 103.47

Then you add -10.12 to 103.47

-10.12 + 103.47 = 92.55

y = 92.55

After 12 weeks, the price of the stocks would be $92.55

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VMariaS [17]

ASA postulate because theres two angles and the side in the middle

3 0

3 years ago

Read 2 more answers

Anyone have the answer for this

sergiy2304 [10]

$\huge\bold{Given:}$

Length of the base = 16 km.

Length of the hypotenuse = 34 km. $\huge\bold{To\:find:}$

✎ The length of the missing leg '' $a$ ".

$\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}$

The length of the missing leg "a" is $\boxed{30\:km}$ .

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}$

Using Pythagoras theorem, we have

$({perpendicular})^{2} + ({base})^{2} = ({hypotenuse})^{2} \\ ⇢ {a}^{2} + ({16 \: km})^{2} = ({34 \: km})^{2} \\ ⇢ {a}^{2} + 256 \: {km}^{2} = 1156 \: {km}^{2} \\ ⇢ {a}^{2} = 1156 \: {km}^{2} - 256 \: {km}^{2} \\ ⇢ {a}^{2} = 900 \: {km}^{2} \\ ⇢a \: = \sqrt{900 \: {km}^{2} } \\ ⇢a = \sqrt{30 \times 30 \: {km}^{2} } \\ ⇢a = 30 \: km$

$\sf\blue{Therefore,\:the\:length\:of\:the\:missing\:leg\:"a"\:is\:30\:km.}$

$\huge\bold{To\:verify :}$

$( {30 \: km})^{2} + ({16 \: km})^{2} =( {34 \: km})^{2} \\ ⇝900 \: {km}^{2} + 256 \: {km}^{2} = 1156 \: {km}^{2} \\⇝1156 \: {km}^{2} = 1156 \: {km}^{2} \\ ⇝L.H.S.=R. H. S$