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Sveta_85 [38]
3 years ago
7

What five features can you observe in the embryos of fish, amphibians, reptiles, birds, and humans in this diagram? In other wor

ds, what do they all have in common?
Backbone

Wings

Horns

Sharp teeth

Four limbs (2 arm buds and 2 leg buds)

Gill Slits

Fur

Claws

Tail

Feathers

Eyes




PLEASE HELPP FAST
Physics
1 answer:
bearhunter [10]3 years ago
6 0
Feathers sharp ,teeth some of them , wings ,backbones
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If an element is a semi-conductor, which classification correctly describes it?
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Metal

Explanation:

semiconductors are materials which have a conductivity between conductors (generally metals)

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2 years ago
Which of the following remains constant during the motion of a projectile fired from a planet?
trapecia [35]

Answer:

C. Horizontal component of velocity

Explanation:

Object in motion stays in motion,

nothing works against its motion in the horizontal direction, unlike in the vertical direction, gravity pulls object down.

8 0
2 years ago
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Zero, a hypothetical planet, has a mass of 5.8 x 1023 kg, a radius of 2.7 x 106 m, and no atmosphere. a 10 kg space probe is to
Tom [10]
To answer these questions just use the equations for potential energy using the mass and heights described. the potential energy at the prescribed heights = the initial kinetic energy required to reach that height.

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3 years ago
Which of the following is not considered a major work flow structure?
mixas84 [53]

Answer:

The correct option is;

D. Fabrication

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Considering each of the options, we have

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E. Continuous flow

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8 0
2 years ago
A planet exerts a gravitational force of magnitude 9e22 N on a star. If the planet were 2 times closer to the star (that is, if
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To solve this problem we will use the related concepts in Newtonian laws that describe the force of gravitational attraction. We will use the given value and then we will obtain the proportion of the new force depending on the Radius. From there we will observe how much the force of attraction increases in the new distance.

Planet gravitational force

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F_p = \frac{GMm}{R^2}

F_p = 9*10^{22}N

Distance between planet and star

r = \frac{R}{2}

Gravitational force is

F = \frac{GMm}{r^2}

Applying the new distance,

F = \frac{GMm}{(\frac{R}{2})^2}

F =  4\frac{GMm}{R^2}

Replacing with the previous force,

F = 4F_p

Replacing our values

F= 4(9*10^{22}N)

F = 36*10^{22}N

Therefore the magnitude of the force on the star due to the planet is  36*10^{22}N

5 0
3 years ago
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