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Hunter-Best [27]
4 years ago
15

The velocity component with which a projectile covers certain horizontal distance is maximum at the moment of? a) Hitting the gr

ound b) Highest point c) Projection d) None of these
Physics
1 answer:
Crazy boy [7]4 years ago
3 0
A) hitting the ground
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5.
Kamila [148]

Answer:  (x - 4)² + (y - 7)² = 9

<u>Explanation:</u>

The equation of a circle is: (x - h)² + (y - k)² = r²    where

  • (h, k) is the center
  • r is the radius

Given: (h, k) = (4, 7)

Find the intersection of the given equation and the perpendicular passing through (4, 7).

3x - 4y = -1

     -4y = -3x - 1

        y=\dfrac{3}{4}x-1

              m=\dfrac{3}{4}      -->      m_{\perp}=-\dfrac{4}{3}

y-y_1=m_{\perp}(x-x_1)\\\\y-7=-\dfrac{4}{3}(x-4)\\\\\\y=-\dfrac{4}{3}x+\dfrac{16}{3}+7\\\\\\y=-\dfrac{4}{3}x+\dfrac{37}{3}

Use substitution to find the point of intersection:

x=\dfrac{29}{5}=5.8,\qquad y=\dfrac{23}{5}=4.6

Use the distance formula to find the distance from (4, 7) to (5.8, 4.6) = radius

r=\sqrt{(5.8-4)^2+(4.6-7)^2}\\\\r=\sqrt{3.24+5.76}\\\\r=\sqrt9\\\\r=3

Input h = 4, k = 7, and r = 3 into the circle equation:

(x - 4)² + (y - 7)² = 3²

(x - 4)² + (y - 7)² = 9

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