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ohaa [14]
3 years ago
15

The total units by an objects as it changes position is called _____ ?

Physics
1 answer:
Alika [10]3 years ago
7 0
Change in position of object = Displacment
You might be interested in
Which of the following best describes the human population from early times to the present?
Makovka662 [10]

Answer:

We have a not significant increase of the population until 1700s or 1800s and then a significant increase growth from these years to the present.

Explanation:

From the figure attached we see the evolution of the human population since early times (1050).

We see that from 1050 until 1750-1850 we have an increase slowly with a low value for the increase per year.

But after these years (1750-1850) we see a considerable increase of the population, like an exponential model.

So then we can conclude in general terms this:

We have a not significant increase of the population until 1700s or 1800s and then a significant increase growth from these years to the present.

7 0
3 years ago
The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hou
Inessa05 [86]

Answer:

a) 4.40 s

b) 2.20 s

Explanation:

Given parameters are:

At constant power  ,

initial speed of the car, v_0=0

final speed of the car, v=32 mph

At full power,

initial speed of the car, v_0=0

final speed of the car, v=64 mph

a)

At constant power, KE = \frac{1}{2} mv^2

At full power, KE = \frac{1}{2} m(2v)^2

So KE_f = 4KE_i

So, time to reach 64 mph speed is 4 times more than the initial time

t = 4*1.10 =4.40 s

b)

v=v_0+at\\a=\frac{v-v_0}{t}=\frac{32-0}{1.1/3600}=104727.27 miles/hours^2

For final 64 mph speed,

v=v_0+at\\t=\frac{v-v_0}{a}=\frac{64-0}{104727.27} = 6.111*10^{-4} hours = 6.111*10^{-4}*3600=2.20 s

7 0
3 years ago
A cloud is drifting across the sky at a constant velocity of 724metersperminute to the east. It is at an altitude of 9,200 meter
alisha [4.7K]

Answer:

The cloud moves 9050 meters to the east in 12.5 minutes.

Explanation:

Let suppose that mass of the cloud is negligible. meaning that effects of gravity are negligible and that altitude of the cloud remains constant. If the cloud drifts at constant velocity, travelled distance is defined by following formula:

\Delta s = v\cdot \Delta t (1)

Where:

v - Velocity, in meters per second.

\Delta t - Time, in seconds.

If we know that v = 724\,\frac{m}{min} and \Delta t = 12.5\,min, then the travelled distance after 12.5 minutes is:

\Delta s = 9050\,m

The cloud moves 9050 meters to the east in 12.5 minutes.

7 0
3 years ago
What do mammoths and tigers need energy for
Sidana [21]
Muscles
.............
3 0
3 years ago
Missy Diwater, the former platform diver for the ringling brothers circus had a kinetic energy of 15,000 joules just prior to hi
Slav-nsk [51]
Kinetic energy=0.5*mass*(velocity^2)
15,000 J=0.5*50*v^2
15,000J=25v^2
600 J=v^2
Velocity= 24.49 ms^-1
5 0
3 years ago
Read 2 more answers
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