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2 years ago

Will Mark Brainly thing please help

Chemistry

1 answer:

irina1246 [14]2 years ago

6 0

Answer:

2CO + O ₂ → 2CO ₂

Explanation:

CO + O ₂ → CO ₂

Left Side

C = 1

O = 3

Right Side

C = 1

O = 2

So we'll balance the oxygen first

2CO + O ₂ → 2CO ₂

Left Side

C = 2

O = 4

Right Side

C = 2

O = 4

Ok so balancing the O has also balanced the C

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Use the following chemical equation to answer the question. 4K(s) + O2(g) → 2 K2O(s). If a staff member at a laboratory has 12.0

Allushta [10]

Answer:14.5 grams of K2O

Explanation:

4 0

2 years ago

The thyroid, parathyroid, and thymus are located in the

Studentka2010 [4]

Answer:

The pineal, hypothalamus, and pituitary are located in the BRAIN

The thyroid, parathyroid, and thymus are located in the THROAT

The adrenals, pancreas, testes, and ovaries are located in the NEAR THE KIDNEY

Explanation:

The pineal, hypothalamus, and pituitary are located in the BRAIN

The thyroid, parathyroid, and thymus are located in the THROAT

The adrenals, pancreas, testes, and ovaries are located in the NEAR THE KIDNEY

3 0

2 years ago

Strontium-90 is a radioisotope that will decrease in mass by one-half every 29 years. How many years will it take for a 10.0-gra

Lelechka [254]

Answer: It will take 29 years for a 10.0-gram sample of strontium-90 to decay to 5.00 grams

Explanation:

Radioactive decay process is a type of process in which a less stable nuclei decomposes to a stable nuclei by releasing some radiations or particles like alpha, beta particles or gamma-radiations. The radioactive decay follows first order kinetics.

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

Half life is represented by $t_{\frac{1}{2}$

$t_{\frac{1}{2}=\frac{0.693}{\lambda}$

$\lambda$ = rate constant

Given : Strontium-90 decreases in mass by one-half every 29 years , that is half life of Strontium-90 is 29 years.

As half life is independent of initial concentration, it will take 29 years for a 10.0-gram sample of strontium-90 to decay to 5.00 grams as the amount gets half.

7 0

3 years ago

A military jet cruising at an altitude of 12.0km and speed of 1300./kmh burns fuel at the rate of 46.2/Lmin. How would you calcu

ira [324]

Answer:

2,452.12 L of fuel the jet consumes on a 1150 km mission.

Explanation:

Speed of the jet = 1300 km/h

1 hour = 60 minutes

$1300 km/h=\frac{1300 km}{60 min}=21.667 km/min$

Rate at which jet consumes fuel = 46.2 L/min

Distance covered by jet by consuming 1 liter fuel or mileage = R

R = $\frac{21.667 km/min}{46.2 L/min}=0.4690 km/L$

The amount of fuel the jet consumes on a 1150 km mission will = V

Amount of fuel = $\frac{Distance}{Mileage}$

$V=\frac{1150 km}{0.4690 km/L}=2,452.12 L$

2,452.12 L of fuel the jet consumes on a 1150 km mission.

3 0

3 years ago

In an experiment to find the concentration of calcium hydroxide in limewater , 25.0 cm3 of limewater needed 18.8 cm3 of 0.0400 m

Andre45 [30]

Answer:

0.01504 mol/dm3

Explanation:

Calcium Hydroxide - Ca(OH)2

Hydrochloric acid - HCl

The reaction between both is given as;

2HCl + Ca(OH)2 --> CaCl2 + 2H2O

2 : 1

The relationship between the concentration and volume is given as;

CaVa / CbVb = na / nb

where a = acid (HCl) and b = base Ca(OH)2

Inserting the values;

0.04 * 18.8 / (Cb * 25) = 2 / 1

0.752 / 25Cb = 2

Cb = 0.752 / 50 = 0.01504

6 0

2 years ago