1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ollegr [7]
3 years ago
6

If the natural abundance of Ag-107 is 51.84% what is the abundance of Ag-109?

Chemistry
1 answer:
ASHA 777 [7]3 years ago
4 0

Answer:

Explanation:

48.16%

Well, both abundances have to total 100% so is Ag-107 is 51.84%, then Ag-109 must be 100 – 51.84 = 48.16%.

Hope This Helps :)

You might be interested in
Which bond type is found in ammonium chloride. Select one: a. metallic b. covalent c. ionic
Flura [38]

Answer:

ionic

Explanation:

In NH4Cl molecule, ionic bond is formed between NH4+ and Cl– ions, 3 covalent bonds are formed between N and three H atoms and one coordinate bond is formed between N and 1 H atom.

HOPE IT HELPS :)

PLEASE MARK IT THE BRAINLIEST!

7 0
3 years ago
Read 2 more answers
0.265g of an organic compound produced an evaporation 102cm³ of vapour at 373k and 775mmHg percentage composition of the constit
kumpel [21]

A. The molecular mass of the compound is 77.9 g/mol

B. The molecular formula of the compound is C₆H₆

<h3><u>Determination of the mole of the compound</u></h3>

We'll begin by calculating the number of mole of compound using the ideal gas equation as shown below:

  • Volume (V) = 102 cm³ = 102 / 1000 = 0.102 L
  • Temperature (T) = 373 K
  • Pressure (P) = 775 mmHg = 775 / 760 = 1.02 atm
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Number of mole (n) =?

n = PV / RT

n = (1.02 × 0.102) / (0.0821 × 373)

n = 0.0034 mole

<h3><u>A.</u><u> Determination of the </u><u>molecular mass</u><u> of the </u><u>compound</u><u>. </u></h3>
  • Mass = 0.265 g
  • Number of mole = 0.0034 mole
  • Molecular mass =?

Molecular mass = mass / mole

Molecular mass = 0.265 / 0.0034

Molecular mass of compound = 77.9 g/mol

<h3><u>B</u><u>. Determination of the </u><u>molecular formula</u><u> of the compound. </u></h3>

We'll begin by calculating the empirical formula of the compound.

  • Carbon (C) = 92.24%
  • Hydrogen (H) = 7.76%

Empirical formula =?

Divide by their molar mass

C = 92.24 / 12 = 7.69

H = 7.76 / 1 = 7.76

Divide by the smallest

C = 7.69 / 7.69 = 1

H = 7.76 / 7.69 = 1

Thus the empirical formula of the compound is CH

Finally, we shall determine the molecular formula.

  • Molecular mass = 77.9 g/mol
  • Empirical formula = CH
  • Molecular formula =?

Molecular formula = empirical × n = molecular mass

[CH]n = 77.9

[12 + 1]n = 77.9

13n = 77.9

Divide both side by 13

n = 77.9 / 13

n = 6

Molecular formula = [CH]n

Molecular formula = [CH]₆

Molecular formula = C₆H₆

Complete Question:

0.265g of an organic compound produced on evaporation 102cm cube of vapour at 373K and 775mmHg. Percentage composition of the constituent elements are 92.24% C and 7.76% H. Find the molecular mass and molecular formula of the composition.

Learn more about ideal gas equation:

brainly.com/question/14364992

Learn more about molecular formular:

brainly.com/question/512891

5 0
2 years ago
How many moles are there in 5.24 Liters of NH3 gas at STP?
igor_vitrenko [27]

Answer:

34.3

Explanation:

3 0
3 years ago
The compound Rh(CO)(H)(PH3)2 forms cis and trans isomers. Use this information
Thepotemich [5.8K]

The geometry of a complex is determined by the number of ligands that surround the central atom/ion. There are four ligands in the complex. The coordination number of the complex is 4. The oxidation number of Rh is zero. The preferred geometrical shape of this complex is square planar.

Complexes are formed when Lewis bases called ligands become attached to a central metal atom or ion. The coordination number of the complex refers to the number of ligands that surround the central metal atom/ion.

In this case, four ligands surround the central Rhodium atom in a zero oxidation state.

Since we were told that the compound exhibits cis/trans isomerism then it can not have a tetrahedral geometry. It must have a square planar geometry as tetrahedral complexes do not exhibit cis/trans isomerism.

The image of the  cis- and trans- geometrical isomers of the compound is attached to this answer.

Learn more: brainly.com/question/9616145

5 0
3 years ago
Classify each of the following reaction as one of the 5 types: 2 Mg + O2 + 2 MgO O double replacement O decomposition O synthesi
san4es73 [151]

Answer:

Synthesis

Explanation:

 The reaction:

                 2Mg + O₂   →   2MgO

This reaction above is a synthesis or combination reaction. In such reaction, several products combines to give a single product.

The formation of a single product from two or more reactants is classified under this type of reaction

The driving force for this reaction type is the large and negative heat of formation of the product.

6 0
3 years ago
Other questions:
  • A compound contains 57.2 percent carbon, 6.1 percent hydrogen, 9.5 percent nitrogen, and 27.2 percent oxygen. What the empirical
    14·1 answer
  • Which substance is the oxidizing agent in this reaction? feo+co→fe+co2 express your answer as a chemical formula?
    10·2 answers
  • Easy Help Please!!!!!!
    12·1 answer
  • How many electrons are shared on the Lewis structure of CH2CL2?
    15·1 answer
  • What is the formula mass of mgcl2
    13·1 answer
  • Most nonmetals form covalent or ionic bonds, depending on the element with which they react. Carbon predominantly forms covalent
    12·1 answer
  • An alcohol is 68.84 % C and 4.962 % H by mass. The rest is oxygen. What is the empirical formula of the alcohol? Enter the eleme
    14·1 answer
  • The diagram below shows the apparatus used to pass a current through copper
    5·1 answer
  • What will a red giant that has a low mass likely become?​
    9·1 answer
  • What is the mass of an object with a density of 1.35 g/ml &amp; a volume of 24 ml?
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!