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ollegr [7]
3 years ago
6

If the natural abundance of Ag-107 is 51.84% what is the abundance of Ag-109?

Chemistry
1 answer:
ASHA 777 [7]3 years ago
4 0

Answer:

Explanation:

48.16%

Well, both abundances have to total 100% so is Ag-107 is 51.84%, then Ag-109 must be 100 – 51.84 = 48.16%.

Hope This Helps :)

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Where do an organisms genes come from?
andriy [413]

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Organisms genes come from both mother and father :3

Explanation:

:3

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3 years ago
A certain automobile contains 4 tires, 2 headlights, 1 steering wheel,
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143 parts I think probably not

5 0
3 years ago
a couple of pennies have a mas of 5.2 grams. Asuming that the pennies are 100% percent copper,how many moles of copper are the p
dangina [55]

Answer:

5.2g copper (Cu) => 0.082 moles copper (2 sig.figs.)

Explanation:

mole conversions:

grams to moles => divide by formula wt.

moles to grams => multiply by formula wt.

gas volumes to moles => divide volume by 22.4Liters/mole (STP conditions only)

This problem:

mass to moles => divide by formula wt.

mass = 5.2g = 5.2g/63.5g/mole = 0.082 moles copper (2 sig.figs.)

5 0
2 years ago
You believe you have cracked a secret code that uses elemental symbols to spell words. The code uses numbers to designate the el
Stells [14]

Explanation:

Atomic numbers for neutral atoms are the same as the number of electrons. The number of electrons are used in writing the subshell notation where we can see the highest princpal quantum number(n).

In order to solve this problem, a good knowledge of the periodic table and shell notation is required.  

For example;  

  Given a number 5;  

     We know the number is made of both the atomic number of the element and the highest quantum number.  

  It is easier for us to know the highest quantum number from the shell notation:  

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        highest principal quantum number is 2

  We are left with atomic number 5-2, which is 3

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Part A.   5,     30,      58,      56,     99,     79,    19,     98,     9

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Part B.   9,    99,    30,     95,     19,     47,     79

             N      U       Fe      Ra      S       Mo     Ta

Learn more:  

s-orbital brainly.com/question/9288609

#learnwithBrainly

4 0
3 years ago
What is the volume of 0.80 grams of o2 gas at stp? (5 points) group of answer choices 0.59 liters 0.56 liters 0.50 liters 0.47 l
Vladimir [108]

Answer:

0.56L

Explanation:

This question requires the Ideal Gas Law:  PV=nRT where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, R is the Ideal Gas constant, and T is the Temperature of the gas.

Since all of the answer choices are given in units of Liters, it will be convenient to use a value for R that contains "Liters" in its units:R=0.0821\frac{L\cdot atm}{mol\cdot K}

Since the conditions are stated to be STP, we must remember that STP is Standard Temperature Pressure, which means T=273.15K and P=1atm

Lastly, we must calculate the number of moles of O_2(g) there are.  Given 0.80g of O_2(g), we will need to convert with the molar mass of O_2(g).  Noting that there are 2 oxygen atoms, we find the atomic mass of O from the periodic table (16g/mol) and multiply by 2:  32g\text{ }O_2=1mol\text{ }O_2

Thus, \frac{0.80g \text{ }O_2}{1} \frac{1mol\text{ }O_2}{32g\text{ }O_2}=0.25mol\text{ }O_2=n

Isolating V in the Ideal Gas Law:

PV=nRT

V=\frac{nRT}{P}

...substituting the known values, and simplifying...

V=\frac{(0.025 mol \text{ }O_2)(0.0821\frac{L\cdot atm}{mol \cdot K} )(273.15K)}{(1atm)}

V=0.56L \text{ } O_2

So, 0.80g of O_2(g) would occupy 0.56L at STP.

5 0
2 years ago
Read 2 more answers
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