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Amanda [17]
3 years ago
10

2. How many moles of copper are needed to react with sulfur to produce 0.25 moles of

Chemistry
1 answer:
dimaraw [331]3 years ago
6 0

Answer:

0.5

Explanation:

Cu       Cu2S

2   :       1 ratio

therefore  0.25 moles of Cu2S * (2 moles of Cu/ 1 mole of Cu2S)

=0.5 moles of Cu

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Imagine that A and B are cations and X, Y, and Z are anions, and that the following reactions occur:
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<span>AX(aq)+BY(aq)→no precipitate
AX(aq)+BZ(aq)→precipitate
this two equations imply
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AX(aq) is soluble and <span>BY(aq) is insoluble

the answer is
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Why is making a peanut pretzel and cereal mixture
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It is two or more objects and different things that can be removed from each other.
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A 40.0 mL sample of 0.18 M HCI is titrated with 0.36 M CoHsNH2. Dctermine the pH at these points: At the beginning (before base
Whitepunk [10]

Answer:

at the beginning:

pH = 0.745

Explanation:

HCl is a strong acid, so:

  • HCl + H2O  → H3O+  +  Cl-

       0.18 M             0.18        0.18.....equilibrium

before base is added:

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⇒ pH = - Log [ H3O+ ] = - Log ( 0.18 )

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8 0
3 years ago
2. Suppose that 21.37 mL of NaOH is needed to titrate 10.00 mL of 0.1450 M H2SO4 solution.
AysviL [449]

Answer:

0.1357 M

Explanation:

(a) The balanced reaction is shown below as:

2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O

(b) Moles of H_2SO_4 can be calculated as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For H_2SO_4 :

Molarity = 0.1450 M

Volume = 10.00 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 10×10⁻³ L

Thus, moles of H_2SO_4 :

Moles=0.1450 \times {10\times 10^{-3}}\ moles

Moles of H_2SO_4  = 0.00145 moles

From the reaction,

1 mole of H_2SO_4 react with 2 moles of NaOH

0.00145 mole of H_2SO_4 react with 2*0.00145 mole of NaOH

Moles of NaOH = 0.0029 moles

Volume = 21.37 mL = 21.37×10⁻³ L

Molarity = Moles / Volume = 0.0029 /  21.37×10⁻³  M = 0.1357 M

7 0
3 years ago
What volume would occupy 90g
Free_Kalibri [48]
45 cm^3 i think? not sure tbh sorry
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2 years ago
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