It is given in the question that,

Since we have the value of r given, so we have to use the formula to find the nth term of the geometric progression, which is

Substituting the values of a and r, we will get

So the correct option is the third option .
Answer: -5x+-10 using the distributive property
Total number of bulbs = 64
Number of defective bulbs = 10
Number of good bulbs = 64 - 10 = 54
P(5 good bulbs) = (54/64)⁵ = (27/32)⁵ = 0.428
Answer: 0.428
Answer:
5
Step-by-step explanation:
So first you need to what is over the four. 6x2=12/4. Okay so what does that equal? 12/4=3. Now we need to solve the first equation. 3+5=8. And the last part. 8-3=5
Answer:
we need a picture...
Step-by-step explanation: