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dmitriy555 [2]
3 years ago
6

What is the range of g

Mathematics
1 answer:
denis23 [38]3 years ago
8 0
The range of g is -3,4
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Estimate 10/12 − 3/8 using benchmark values. Your equation must show the estimate for each fraction and the final estimate for t
Maksim231197 [3]

Answer: \frac{11}{24}

Step-by-step explanation:

Give expression is,

\frac{10}{12}-\frac{3}{8}

Since L.C.M ( 12, 8 ) = 24

=\frac{10\times 2}{12\times 2}-\frac{3\times 3}{8\times 3}

=\frac{20}{24}-\frac{9}{24}

=\frac{20-9}{24}

=\frac{11}{24}

\text{Hence, }\frac{10}{12}-\frac{3}{8}=\frac{11}{24}

8 0
3 years ago
A 26-foot long ladder is leaning against a building at a 60 degree angle with the ground. Which of the following equations can y
Sati [7]

Answer:

22.5 feet (to the nearest tenth).

Step-by-step explanation:

The equations have not been given but still the question can be solved. The ladder lying with a building makes a right angled triangle, in which the ladder is the hypotenuse, the building is the perpendicular, and the ground is the base. The length of the ladder (hypotenuse) is 26 feet and the angle with the ground is 60 degrees. The required length to be found is the length of the building (perpendicular). So the following formula will be used:

sin θ = Perpendicular/Hypotenuse.

Substituting in the equation gives:

sin60 = p/26.

p = 26*sin60.

p = 22.5 (to the nearest tenth).

The approximate height of the building is 22.5 feet!!!

4 0
3 years ago
Read 2 more answers
Cheryl has $56 and wants to buy as many notebooks as she can to donate to her school. If each notebook costs $1.60, which inequa
natka813 [3]
The answer is B because n is equal to the number of notebooks. you can not exceed the amount of money that you have to buy the notebooks
8 0
3 years ago
Read 2 more answers
If $x$, $y$, and $z$ are positive integers such that $6xyz+30xy+21xz+2yz+105x+10y+7z=812$, find $x+y+z$.
harina [27]

Answer:

10

Step-by-step explanation:

When we simplify we get $$z(6xy+21x+2y+7)+30xy+105x+10y=812.$$

Then we continue to factor to get: (z+5)(6xy+21x+2y+7)&=847.

We then see that we can factor (6xy+21x+2y+7) into (z+5)(3x+1)(2y+7)&=847.

we then do the prime factorization of 847, which i think is,  7*11*11. we have to find the numbers that multiply to 847 and then plug them into z+5, 3x=1,2y+7.

It has to be a positive, non-negative integer, right?

We also see that 3x+1=11 so we see that x=10/3 (which wont work).

So 3x+1=7, so x=2.

So 11 has to be in another term. It has to be in 2y+7=11 so y=2

for the last term we get z+5=11 so z=6

2+2+6=10

Hope this helps and if you want please consider giving me brainliest. :)

8 0
3 years ago
Mark said he can decompose the fraction 5/6 into three numerator.Is this possible? Explain.
OlgaM077 [116]
Ni because if you divide or mulriply the denominator you have to multiply or divide the numerator by the same amount. It is not possible dince you can divide the denominator by 2 to get 3 but you cant divude 5 by 2 and get an evn number
4 0
3 years ago
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