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3 years ago

Find the sum: 6/x-4+5/x О 11/2x-4 O 11x-24/x^2-4x O 11x-20/x^2-4x

Mathematics

2 answers:

Olegator [25]3 years ago

8 0

Answer:

(11 x - 20)/(x (x - 4)) = 11x-20/x^2-4x

Step-by-step explanation:

Simplify the following:

6/(x - 4) + 5/x

Put each term in 6/(x - 4) + 5/x over the common denominator x (x - 4): 6/(x - 4) + 5/x = (6 x)/((x - 4) x) + (5 (x - 4))/((x - 4) x):

(6 x)/(x (x - 4)) + (5 (x - 4))/(x (x - 4))

(6 x)/((x - 4) x) + (5 (x - 4))/((x - 4) x) = (6 x + 5 (x - 4))/((x - 4) x):

(6 x + 5 (x - 4))/(x (x - 4))

5 (x - 4) = 5 x - 20:

(5 x - 20 + 6 x)/(x (x - 4))

Grouping like terms, 6 x + 5 x - 20 = (6 x + 5 x) - 20:

((6 x + 5 x) - 20)/(x (x - 4))

6 x + 5 x = 11 x:

Answer: (11 x - 20)/(x (x - 4))

JulijaS [17]3 years ago

3 0

Answer:

Step-by-step explanation:

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2 years ago

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<h3>Answer: </h3><h3>Yes, the triangles are similar</h3><h3>AC = 6</h3>

======================================================

Explanation:

Focus on triangle ABC. Let's find the missing angle

A+B+C = 180

113+B+22 = 180

B+135 = 180

B = 180-135

B = 45

Between the triangles, have two pairs of angles that are congruent

A = D = 113

B = E = 45

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