Let y be the temperature
Let m be the rate of temperature drop in degrees per hour
Let x be the number of hours elapsed since 8PM
The initial temperature (at x = 0) is 0
y = mx
Four hours from 8 PM, the temperature was -16.8 degrees
-16.8 = m(4)
m = -4.2 degrees per hour
At 9PM, one hour will have elapsed.
y = -4.2(1)
y = -4.2 degrees
Answer:
0.79
Step-by-step explanation:
Here,
Let X be the event that the flights depart on time
Let Y be the event that flights arrive on time
So,
X∩Y will denote the event that the flights departing on time also arrive on time.
Let P be the probability
P(X∩Y)=0.65
And
P(X)=0.82
We have to find P((Y│X)
We know that
P((Y│X)=P(X∩Y)/P(X) )
=0.65/0.82
=0.79
So the probability that a flight that departs on schedule also arrives on schedule is: 0.79
Answer:
In the area that she observed, the water level fell 13.64mm over 6.4 years, for an average annual rate of change of: -13.64 ÷ 6.2 = -2.2 mm/ year.
Answer:
f(g) = -15x^2 + 15x + 2.
g(-2) = 18.
Step-by-step explanation:
f(g) = -5(3x^2 - 3x) + 2
= -15x^2 + 15x + 2.
g(-2) = 3(-2)^2 - 3(-2)
= 12 + 6
= 18.
Answer:
10 • (x - 2y + 3z)
? if thats the answer.
and y = 5/2 = 2.500 for the - 2y = -5 one. if they are both combined please comment under mine.
