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DIA [1.3K]
3 years ago
15

If we decrease the amount of force, and keep all other factors the same, what will happen to the amount of work? The amount of w

ork will go down because the distance will decrease. The amount of work will go up because the distance will decrease. The amount of work will go down because the distance will increase. The amount of work will go up because the distance will increase.
Physics
1 answer:
Harrizon [31]3 years ago
3 0

Answer: the amount of work will increase.

Explanation: ur welcome

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if a material has a half-life of 24 hours, how long do you have to wait until the amount of radioisotope is 1/4 its original amo
7nadin3 [17]

Answer:

48 hours

Explanation:

Using the formula,

R/R' = 2ᵃ/ᵇ..................... Equation 1

Where R = Original amount, R' = Radioactive remain, a = Total time, b = half life.

Given: b = 24 hours,

Let: R = X, then R' = X/4.

Substitute into equation 1

X/(X/4) = 2ᵃ/²⁴

4 = 2ᵃ/²⁴

2² = 2ᵃ/²⁴

Equating the base and solving for a

2 = a/24

a = 24×2

a = 48 hours.

Hence the time = 48 hours

3 0
3 years ago
A camcorder has a power rating of 14 watts. If the output voltage from its battery is 2 volts, what current does it use?
HACTEHA [7]

Power = (voltage) x (current)

If the camcorder is USING 14 watts of electrical power right now, then . . .

14 watts = (2 volts) x (current)

Divide each side by (2 volts):

Current = (14 watts) / (2 volts)

Current = (14 V-A) / (2 V)

<em>Current = 7 Amperes</em>

7 0
3 years ago
16. A pug puppy is sitting on a skateboard. The pug has a mass of 2.4 kg, and the skateboard has a mass
kramer

Answer:

12 N

Explanation:

Use Newton's second law:

∑F = ma

F = (2.4 kg + 1.3 kg) (3.2 m/s²)

F = 11.84 N

Rounded to two significant figures, the force is 12 N.

4 0
3 years ago
A spring extends by .16 meters when pulled with 20 N of Force. What is the Potential Energy in the spring at this extension?
Yuri [45]

Answer:

Potential energy = 1.6 J

Work done = -1.6 J

Explanation:

Potential Energy in the spring at this extension?

The potential energy U in the spring is U = 1/2kx² where k = spring constant = F/x where F = force = 20 N and x = extension = 0.16 m. So k = 20 N/0.16 m = 125 N/m

U = 1/2kx²

= 1/2 × 125 N/m × (0.16 m)²

= 1.6 J

What is the work done to extend the spring. 16 meters

Work done W = U₁ - U₂ where U₁ = initial potential energy = 0 and U₂ = final potential energy = 1.6 J

W = 0 - 1.6 J

   = -1.6 J

4 0
3 years ago
Define one metre length.​
OleMash [197]

Answer:

The metre is currently defined as the length of the path travelled by light in a vacuum in 1299 792 458 of a second

4 0
3 years ago
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