Assuming constant acceleration <em>a</em>, the object has undergoes an acceleration of
<em>a</em> = (50 m/s - 100 m/s) / (25 s) = -2 m/s²
Then the net force has a magnitude <em>F</em> such that, by Newton's second law,
<em>F</em> = (75.0 kg) <em>a</em>
<em>F</em> = (75.0 kg) (-2 m/s²)
<em>F</em> = -150 N
meaning the object is acted upon by a net force of 150 N in the direction opposite the initial direction in which the object is moving.
Answer:
a) F = -1035.385 N
b) Backwards
c) s = 15.60 m
Explanation:
Given information
= Initial Speed of Car = 15.0 m/s
= Final Speed of Car = 9.00 m/s
= Breaking Time = 1.30 s
= Mass of Car = 1040 kg
Part (a)
To find the force exerted on the car we use the following formula
Where
= Force = unknown
= Mass of Car = 1040 kg
= Acceleration of Car / Deceleration of Car = unknown
To find the force (F) we need to first find the deceleration rate (a)
To find the deceleration rate we use the following formula
Inputting the given values
To find the force
Part (b)
Since the value of F is negative this means the the force was opposite the direction of motion, hence the force was backwards.
Part (c)
To find the total distance the car moved while braking we use the following formula
Where
= distance traveled
Inputting the values given
Nutrients found in packed items include carbohydrates, fats and proteins and the amount of nutrients present in them is found in calories/grams.
<h3>What are macronutrients?</h3>
Macronutrients are nutrients that contain calories that must be consumed in the diet to perform metabolic functions.
These macronutrients are specified in packed foods, and include proteins, carbohydrates and lipids.
Macronutrients provide 4 calories (proteins and carbohydrates) or 9 calories per gram (fats).
In conclusion, nutrients include carbohydrates, fats (lipids) and proteins and their proportions are expressed in grams.
Learn more about macronutrients here:
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<em>Angle of Dip is the angle in the vertical plane aligned with magnetic north (the magnetic meridian) between the local magnetic field and the horizontal.</em>
Solution:
a) We know acceleration due to gravity, g = GM/r²
Differential change, dg/dr = -2GM/r³
Here, r = 50*Rh = 50*2GM/c² = 100GM/c
²
My height, h=dr = 1.7 m
Difference in gravitational acceleration between my head and my feet, dg = -10 m/s²
or, dg/dr = -10/1.7 = -2GM/(100GM/c²)³
or, 5.9*100³*G²*M² = 2c⁶
or, M = 0.59*c³/(1000G) = 2.39*1032 kg = [(2.39*1032)/(1.99*1030 )]Ms = 120*Ms
Mass of black hole which we can tolerate at the given distance is 120 time the mass of Sun.
b) This limit an upper limit ,we can tolerate smaller masses only.
