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1 year ago

A 190 mH inductor is connected to an emf given by

Physics

1 answer:

Bas_tet [7]1 year ago

7 0

(a) The reactance of the inductor is 25.46 ohms.

(b) The expression for the current through the inductor is I(t) = (6.32 A) sin(134t)

<h3>Ractance of the inductor</h3>

The reactance of the inductor is calculated as follows;

XL = ωL

where;

ω is angular frequency
L is 190 mH

v(t) = (161 V) sin(134t)

v(t) = V sin(ωt)

The reactance of the inductor is calculated as follows;

XL = (134) x (190 x 10⁻³)

XL = 25.46 ohms

<h3>Peak current in the circuit</h3>

I₀ = V₀/XL

I₀ = (161) / (25.46)

I₀ = 6.32 A

<h3>Expression for the current through the inductor</h3>

I(t) = (6.32 A) sin(134t)

Learn more about inductance here: brainly.com/question/16765199

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The moment of water from ocean through the atmosphere and back

melisa1 [442]

The water cycle is all about storing water and moving water on, in, and above the Earth. Although the atmosphere may not be a great storehouse of water, it is the superhighway used to move water around the globe. Evaporation and transpiration change liquid water into vapor, which ascends into the atmosphere due to rising air currents. Cooler temperatures aloft allow the vapor to condense into clouds and strong winds move the clouds around the world until the water falls as precipitation to replenish the earthbound parts of the water cycle. About 90 percent of water in the atmosphere is produced by evaporation from water bodies, while the other 10 percent comes from transpiration from plants.

There is always water in the atmosphere. Clouds are, of course, the most visible manifestation of atmospheric water, but even clear air contains water—water in particles that are too small to be seen. One estimate of the volume of water in the atmosphere at any one time is about 3,100 cubic miles (mi3) or 12,900 cubic kilometers (km3). That may sound like a lot, but it is only about 0.001 percent of the total Earth's water volume of about 332,500,000 mi3 (1,385,000,000 km3), If all of the water in the atmosphere rained down at once, it would only cover the globe to a depth of 2.5 centimeters, about 1 inch.

6 0

2 years ago

Read 2 more answers

8) 8 resistor is connected in **parallel** with a 6 resistor. This

lyudmila [28]

Answer:

The equivalent resistance of the combination is 3.42 ohms.

Explanation:

We have,

8 ohms resistor is connected in parallel with a 6 ohms resistor. It is required to find the equivalent resistance of this combination.

For a parallel combination, the equivalent resistance is given by :

$\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}$

Plugging the values of R₁ and R₂, we get :

$\dfrac{1}{R_{eq}}=\dfrac{1}{8}+\dfrac{1}{6}\\\\R_{eq}=3.42\ \Omega$

So, the equivalent resistance of the combination is 3.42 ohms.

4 0

3 years ago

In which of these situations, is mechanical energy being conserved? (Neglect, air resistance, friction, and breaking) Check all

Amiraneli [1.4K]

1) Mechanical energy is conserved in all the situations mentioned

2) True

3) Potential energy

4) The potential energy is 490 J

5) The potential energy is 750,000 J

Explanation:

The mechanical energy of an object is the sum of its potential energy (PE) and its kinetic energy (KE):

$E=PE+KE$

When there are no conservative forces acting on the object (i.e. air resistance of friction), the mechanical energy is always conserved, so it is constant:

$E=const.$

This means that there is a continuous conversion between potential energy and kinetic energy.

In all the examples mentioned here, there are no air resistance or friction acting on the system: therefore, mechanical energy is conserved in all cases.

The potential energy of the object falling to the ground is given by

$PE=mgh$

where

m is the mass

g is the acceleration of gravity

h is the height of the object above the ground

While the kinetic energy is given by

$KE=\frac{1}{2}mv^2$

where

v is the speed of the object

As the object falls, its height h decreases, while the speed v increases: therefore, the potential energy decreases and it is converted into kinetinc energy, which increases.

The energy possessed by an object due to its position is called potential energy. It can be of two types:

- Gravitational potential energy: it is the energy possessed by an object due to its position in a gravitational field. It is given by

$PE=mgh$

where m is the mass, g the acceleration due to gravity, h the height of the object

- Elastic potential energy: it is the energy stored in an elastic object which is compressed or stretched - it is given by

$PE=\frac{1}{2}kx^2$

where k is the spring constant and x the elongation of the object relative to its equilibrium position.

The (gravitational) potential energy stored in the block is calculated as

$PE=mgh$

where:

m = 10 kg is the mass of the block

$g=9.8 m/s^2$ is the acceleration due to gravity on Earth's surface

h = 5 m is the height of the object above the ground

Substituting, we find the potential energy:

$PE=(10)(9.8)(5)=490 J$

The potential energy of the elevator is given by

$PE=mgh$

In this case, we have

h = 500 m (height of the elevator)

W = 1500 N (weight of the elevator)

We also know that the weight is the product of mass and acceleration due to gravity:

$W=mg$

So we can rewrite the first equation as

$PE=Wh$

And substituting, we find

$PE=(1500)(500)=750,000 J$

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3 years ago

The north magnetic pole of a compass magnet points towards earth's geographic _____ and earth's magnetic _____.

Pavel [41]

The answer is
North pole; south pole
I hope this helps

7 0

3 years ago

Read 2 more answers

You are inside a room, 15 m from the west wall, which has two doors (similar to slits) and you are centered between the two open

andre [41]

Answer:

The distance of first minimum from central maxima is 4.25 m

The spacing between maxima in sound intensity is 8.5 m.

Explanation:

Given that,

Distance D= 15 m

Frequency = 200 Hz

distance between slits a=3 m

We know that,

The width of fringe,

$\beta=\dfrac{\Lambda D}{a}$

$\beta=\dfrac{vD}{fa}$

(a). We need to calculate the distance of first minimum from central maxima

Using formula for distance

$d=\dfrac{\beta}{2}$

$d=\dfrac{vD}{2fa}$

Put the value into the formula

$d=\dfrac{340\times15}{2\times200\times3}$

$d=4.25\ m$

(b). We need to calculate the spacing between maxima in sound intensity

Using formula for the distance of first maxima

$d'=2d$

$d'=2\times4.25$

$d'=8.5\ m$

Hence, The distance of first minimum from central maxima is 4.25 m

The spacing between maxima in sound intensity is 8.5 m.

6 0

3 years ago