(a) The reactance of the inductor is 25.46 ohms.
(b) The expression for the current through the inductor is I(t) = (6.32 A) sin(134t)
<h3>Ractance of the inductor</h3>
The reactance of the inductor is calculated as follows;
XL = ωL
where;
- ω is angular frequency
- L is 190 mH
v(t) = (161 V) sin(134t)
v(t) = V sin(ωt)
The reactance of the inductor is calculated as follows;
XL = (134) x (190 x 10⁻³)
XL = 25.46 ohms
<h3>Peak current in the circuit</h3>
I₀ = V₀/XL
I₀ = (161) / (25.46)
I₀ = 6.32 A
<h3>Expression for the current through the inductor</h3>
I(t) = (6.32 A) sin(134t)
Learn more about inductance here: brainly.com/question/16765199
