Question

A 190 mH inductor is connected to an emf given by

Answer 1

(a) The reactance of the inductor is 25.46 ohms.

(b) The expression for the current through the inductor is I(t) = (6.32 A) sin(134t)

Ractance of the inductor

The reactance of the inductor is calculated as follows;

XL = ωL

where;

• ω is angular frequency
• L is 190 mH

v(t) = (161 V) sin(134t)

v(t) =  V sin(ωt)

The reactance of the inductor is calculated as follows;

XL = (134) x (190 x 10⁻³)

XL = 25.46 ohms

Peak current in the circuit

I₀ = V₀/XL

I₀ = (161) / (25.46)

I₀ = 6.32 A

Expression for the current through the inductor

I(t) = (6.32 A) sin(134t)

Learn more about inductance here: brainly.com/question/16765199