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3 years ago

What is the net force experienced by the rope? Include both the magnitude and direction

Physics

1 answer:

Lapatulllka [165]3 years ago

3 0

Answer:

All the physical world objects that comers in the contact to exert the force to each other. The contact forces are different from their names and what type of force they exert.

Explanation:

The cables and the ropes are the useful objects that exert the forces that can efficiently transfer the force from a significant distance.

It is noted that tension is a type of force that the rope can not simply push it away effectively. When push happened with rope, the rope goes to slack and lose all the tension that pulls at the first place. Tension only pull objects.

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Calculate the heat added to 3kg of water if the temperature increases from 30 C to 60 C.

sweet-ann [11.9K]

Answer: B is right

Explanation: Heat Q = m Cv ΔT = 3.0 kg · 4186 J / (kg·K) · 30 K≈ 376 740 J

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3 years ago

A fixed coil of wire with 10 turns and an area of 0.055 m2 is placed in a perpendicular magnetic field. This field oscillates in

Blababa [14]

Answer:

Part a)

Average EMF for half cycle is

$E_{avg} = 2.64 V$

Part b)

For one complete cycle we will have

$E_{avg} = 0$

Part c)

Maximum induced EMF will be at

t = 0.025 s and 0.075 s

minimum induced EMF is at

t = 0.05s and 0.1 s

Explanation:

As we know that magnetic field is oscillating in direction as well as magnitude

so induced EMF is given as

$E = NBA\omega sin(\omega t)$

Part a)

For average value of EMF from positive maximum to negative maximum which is equal to half cycle

so we have

$E_{avg} = NBA\omega \frac{2}{T}\int_0^{T/2} sin(\omega t) dt$

$E_{avg} = \frac{2NBA\omega}{\pi}$

$E_{avg} = \frac{2(10)(0.12)(0.055)(2\pi (10))}{\pi}$

$E_{avg} = 2.64 V$

Part b)

For one complete cycle we will have

$E_{avg} = NBA\omega \frac{1}{T}\int_0^T sin(\omega t) dt$

$E_{avg} = 0$

Part c)

Maximum induced EMF will be at

$t = \frac{T}{4} and \frac{3T}{4}$

here we know

$T = \frac{1}{f} = 0.1 s$

t = 0.025 s and 0.075 s

minimum induced EMF is at

$t = \frac{T}{2} and T$

so it is

t = 0.05s and 0.1 s

8 0

4 years ago

A stalled car is being pushed up a hill at constant velocity by three people. the net force on the car is

frosja888 [35]

I think you need more information like the force of gravity and the force of the three people. Once you combine the two, however, you should get the net force.

6 0

3 years ago

Explain why it is easier to climba mountain on a zigzag path rather than one straight up the side. Is your increase in gravitati

DerKrebs [107]

Answer:

it is easier in zig zag because youll fell less tired and feel more energetic and it will will feel as if it were shorter to go zig zag

3 0

4 years ago

Air pressure is 1.0 · 105 N/m2, air density is 1.3 kg/m3, and the density of soft drinks is 1.0 · 103 kg/m3. If one blows carefu

natita [175]

Answer:

v = 27.456 m/s

Explanation:

The support pressure needed of the water in the straw can be calculated by the formula

Given that,

P = r*g*h

= 1000*9.8*0.05 Pa.= 490 Pa

This pressure is compensated by 0.5*r*v^2 of the air,

Hence,

0.5*1.3*v^2 = 490

velocity of air blown into the straw =

v = 27.456 m/s

8 0

3 years ago