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3 years ago

7

MARKING BRAINLIEST!!! NOOOOOOOOOOOO LINKS OR I WILLLLLLLLL REPORT YOU!

2 answers:

Leni [432]3 years ago

3 0

Answer:

Explanation:

Reverse

AfilCa [17]3 years ago

3 0

Answer:

dynamic equilibrium

Explanation:

Substances transition between the reactants and products at equal rates, meaning there is no net change. Reactants and products are formed at such a rate that the concentration of neither changes.

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Which sound waves in the electromagnetic spectrum are considered low energy waves

Mariulka [41]

Radio waves are the waves with the lowest energy in the electromagnetic spectrum. X-rays and gamma rays are the highest. Sound is not part of the electromagnetic spectrum.

7 0

3 years ago

According to Coulomb's law, if the separation between two particles of the same charge increases four times, the potential energ

Lera25 [3.4K]

Answer:

c. V = k Q1 * Q2 / R1 potential energy of Q1 and Q2 separated by R

V2 / V1 = (R1 / R2) = 1/4

V2 = V1 / 4

8 0

3 years ago

What is the distance a bike travels at 38 km/he for 4.5 seconds?

marshall27 [118]

Answer:

2.36m/s

Explanation:

first you have change 38km/hr into m/s

then divide your answer with 4.5

4 0

3 years ago

a radio station broadcast a frequency 90500 Hz. these radio waves travel at speed of 30000 m/s. what is the wavelength of the ra

Feliz [49]

Answer:

0.331m

Explanation:

wave equation: v=f λ

v=30000m/s

f=90500 Hz

λ= $\frac{v}{f}$

λ= $\frac{30000}{90500}$

λ= 0.311m

5 0

2 years ago

During a tennis volley, a ball that arrives at a player at 40 m/s is struck by the racquet and returned at 40 m/s. The other pla

Butoxors [25]

Answer:Racquet force is twice of Player force

Explanation:

Given

ball arrives at a speed of $u=-40\ m/s$

ball returned with speed of $v=40\ m/s$

average Force imparted by racquet on the ball is given by

$F_{racquet}=\frac{m(v-u)}{\Delta t}$

where $m=mass\ of\ ball$

$\Delta t=$ time of contact of ball with racquet

$F_{racquet}=\frac{m(40-(-40))}{\Delta t}$

$F_{racquet}=\frac{80m}{\Delta t}-----1$

When it land on the player hand its final velocity becomes zero and time of contact is same as of racquet

$F_{player}=\frac{m(0-40)}{\Delta t}$

$F_{player}=\frac{-40m}{\Delta t}-----2$

From 1 and 2 we get

$F_{racquet}=-2F_{player}$

Hence the magnitude of Force by racquet is twice the Force by player

5 0

3 years ago