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3 years ago

The study of fluids

Mathematics

1 answer:

Elenna [48]3 years ago

6 0

Replace m with 46x10^4 in the equation and solve.

0.036(46x10^4)^3/4 = 635.87

Round to 636

The answer is A.

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Draw the graph of 4x-1 on the grid

Natasha2012 [34]

Answer:

btw look up desmos graphing calculator

Step-by-step explanation:

5 0

3 years ago

Write 1. 995x10^-22 in standard form.

densk [106]

That would be 177.5 in standard form.

5 0

3 years ago

What is LCM of 2 4 8

slavikrds [6]

Answer:

the LCM would be 8 based on the following set of multiples: Multiples of 2: 2, 4, 6, 8, 10, 12, 14, ... Multiples of 8: 8, 16, 24, 32, 40, 48, 56, ...

Step-by-step explanation:

3 0

3 years ago

A mistake was made in mixing the lemonade—<br> PLEASE HELP!!

beks73 [17]

Answer:

Part A:

$4 + x = y$

$0.5*4 + 1*x = 0.7*y$

$x = 8/3\ quarts\ of\ 100\%\ solution$

$y = 20/3\ quarts\ of\ 70\%\ solution$

Part B:

$x + y = 10$

$2x + 3y = 23$

$x = 7$ and $y = 3$

Step-by-step explanation:

Part A:

The inicial concentration of the lemonade is 50%, and the volume is 4 quarts, and we will add x quarts of a lemonade with a concentration of 100%, so the total volume will be y, and the concentration will be 0.7, so we have that:

$4 + x = y$

$0.5*4 + 1*x = 0.7*y$

Using the value of y from the first equation in the second one, we have:

$2 + x = 0.7*(4 + x)$

$2 + x = 2.8 + 0.7x$

$0.3x = 0.8$

$x = 8/3\ quarts$

$y = 4 + 8/3 = 20/3\ quarts$

Part B:

If he shoots a total of ten targets, we can write the equation:

$x + y = 10$

Each stationary target is 2 points, and each moving target is 3 points, so if the total points is 23, we have:

$2x + 3y = 23$

If we subtract the second equation by two times the first one, we have:

$2x + 3y - 2*(x + y) = 23 - 2*10$

$2x + 3y - 2x - 2y = 23 - 20$

$y = 3$

$x + 3 = 10$ ⇒ $x = 7$

4 0

3 years ago

-1(x+5)=3[x+(2x-1)]<br> solved and justified each step

madreJ [45]

Answer:

Step-by-step explanation:

$-1(x+5)=3[x+2x-1)]\\\\\text{for}\ -1(x+5):\ \text{distribtutive property}\\\text{for}\ [x+(2x-1)]:\ \text{associative property}\\\\(-1)(x)+(-1)(5)=3[(x+2x)-1]\\-x-5=3(3x-1)\\\\\text{for}\ 3(3x-1):\ \text{distributive property}\\\\-x-5=(3)(3x)+(3)(-1)\\-x-5=9x-3\\\\\text{for the equation}:\ \text{addition property of equality}\\\\-x-5=9x-3\qquad\text{add 5 to both sides}\\-x-5+5=9x-3+5\\-x=9x+2\\\\\text{for the equation:}\ \text{subtraction property of equality}\\\\-x=9x+2\qquad\text{subtract}\ 9x\ \text{from both sides}$

$-x-9x=9x-9x+2\\-10x=2\\\\\text{for the equation:}\ \text{division property of equality}\\\\-10x=2\qquad\text{divide both sides by -10}\\\dfrac{-10x}{-10}=\dfrac{2}{-10}\\x=-0.2$

$\text{Distributive property:}\ a(b+c)=ab+ac\\\text{Associative property:}\ (a+b)+c=a+(b+c)$

6 0

3 years ago

The study of fluids​

The study of fluids