The first organisms are autotrophs (primary producers)
The answer is (3) 11.2 L of N2(g). When the choices are all gases, the number of molecules depends on the molar number of the gas. Under the condition of STP, the molar number of a gas is depends on volume only. So the same volume of gas has the same number of molecules.
Answer:
Q = 63.75J
Explanation:
Mass = 2.5g
Initial temperature (T1) = 25°C
Final temperature (T2) = 50°C
Specific heat capacity of Mg = 1.020J/g°C
Heat energy = ?
Heat Energy (Q) = mc∇T
Q = heat energy
M = mass of substance
C = specific heat capacity of substance
∇T = change in temperature = T2 - T1
Q = mc∇T
Q = mc(T2 - T1)
Q = 2.5 × 1.020 × (50 - 25)
Q = 2.55 × 25
Q = 63.75J
The heat energy required to raise magnesium metal from 25°C to 50°C is 63.75J
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At first scientists/researchers observe a natural phenomenon. after enough observation, they make predictions why that phenomenon is happening and the reasons that lead to that particular phenomenon. then they generate scientific hypothesis to explain that phenomenon and after getting enough data they develop tests and perform experiments. And check the results they get and at last based on the results they conclude what actually is happening.
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
Answer:
CH₄ - 162 ⁸C
CH₃CH₃ -88.5 ⁸C
(CH₃)₂ CHCH₂CH₃ 28 ⁸C
CH₃3(CH2)₃CH₃ 36 ⁸C
CH₃OH 64.5 ⁸C
CH₃CH₂OH 78.3 ⁸C
CH₃CHOHCH₃ 82.5 ⁸C
C₅H₉OH 140 ⁸C
C₆H₅CH₂OH 205 ⁸C
HOCH₂CHOHCH₂OH 290 ⁸C
Explanation:
To answer this question we need first to understand that for organic compounds:
a. Non polar compounds have lower boiling points than polar ones of similar structure and molecular weight.
b. Boiling points increase with molecular weight. In alkane compounds if we compare isomers, the straight chain isomer will have a higher boiling point than the branched one (s) because of London dispersion intermolecular forces.
a. The introduction of hydroxyl groups increase the intermolecular forces and hence the boiling points because the electronegative oxygen, and, more importantly the presence of hydrogen bonds.
Considering the observations above, we can match the boiling points as follows:
CH₄ - 162 ⁸C
CH₃CH₃ -88.5 ⁸C
(CH₃)₂ CHCH₂CH₃ 28 ⁸C
CH₃3(CH2)₃CH₃ 36 ⁸C
CH₃OH 64.5 ⁸C
CH₃CH₂OH 78.3 ⁸C
CH₃CHOHCH₃ 82.5 ⁸C
C₅H₉OH 140 ⁸C
C₆H₅CH₂OH 205 ⁸C
HOCH₂CHOHCH₂OH 290 ⁸C
Note: There was a mistake in the symbols used for the 162 and 88.5 values which are negative and correspond to the common gases methane and ethane
