Answer: The freezing-point depression constant (Kf) of nitrobenzene is 
Explanation:
Depression in freezing point is given by:

= Depression in freezing point
i= vant hoff factor = 1 (for non electrolyte nitrobenzene)
= freezing point constant = ?
m= molality

Weight of solvent = 20 g = 0.02 kg
mass of solute (ethanol) = 1.0 g
Molar mass of ethanol = 46 g/mol


Thus freezing-point depression constant (Kf) of nitrobenzene is 
4.186 Joules equals 1 cal.
1 cal is the amount of energy needed to increase in 1ºC the temperature of 1 gram of water. If we add to 15.5 grams of water 4350 Joules, we are adding approximately 1039.2 cal. (4350÷4.186≈1039.2)
This energy though is being divided by all the gram in the water. 1039.2cal÷15.5g≈67.0cal/g
4.35kJ would increase the water's temperature in approximately 67ºC, putting it at 72ºC. The state would remain the same - liquid - though much closer to boil.
Mg(ClO3)2 + 2NaOH → Mg(OH)2 + 2NaClO3.
This is about as hard a question as you can get in beginning chemistry. You have to figure out which chemical between the two reactants is the LEAST number of moles before you can do anything about the products. Read that sentence over again carefully and keep in mind what least means. It's the key to the entire question.
For every mole of Mg(ClO3)2 you need two moles of NaOH. That's what the balanced equation tells you. The big number on the left of the chemical is where I'm getting 1 to 2. One is in front of Mg(ClO3)2 and 2 is to the left of NaOH
So you have 2.72 moles of Mg(ClO3)2. You would need to have 2.72*2 moles of NaOH which is 5.44 moles of NaOH. Do you have enough NaOH. (I should hear a resounding NO.) So the limiting reactant is NaOH. You only have 3.14 moles of NaOH. Now you can start getting the answer to the question
You now need to set up the same ratio for the Mg(OH)2
For every 2 moles of NaOH you get 1 mole of Mg(OH)2. The proportion is
NaOH/Mg(OH)2 = 2/1
NaOH = 3.14 moles
3.14 / Mg(OH)2 = 2/1 Cross multiply
3.14 = 2 * Mg(OH)2 Divide by 2
3.14/2 = Mg(OH)2 Combine the left
1.57 = Mg(OH)2 Answer
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I'll let you work through the second blank. I'm not completely heartless so I'll tell you that the ratio is 1:1 and that the answer should be 3.14
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Answer Box one = 1.57
Answer Box Two = 3.14
Answer:
C. They have the same number of protons.
Explanation:
Even though in isotopes, there's uneven number of neutrons, there's always same number of protons.
Hope it helps.
Answer: option C. Critical temperature
Explanation: