1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BlackZzzverrR [31]
3 years ago
15

An udentified substance, Y, was thought to be one of the following three compounds.

Chemistry
1 answer:
arlik [135]3 years ago
7 0
This is more logic deduction than having learnt this, but i would think Y = B because it hasnt affected the melting point, implying its the same substance? hope this helps a bit :)
You might be interested in
PLEASE HELP !! ILL GIVE BRAINLIEST !! 100 POINTS IF YOUR GOOD AT CHEMISTRY AND BIOLOGY .
lesya692 [45]

Answer:

C.

Explanation:

if I am wrong I am so sorry

4 0
2 years ago
Read 2 more answers
A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place over the next fe
Fantom [35]

Answer:

A

Explanation:

The molecules in both metal and surrounding air will start moving slower because of the sudden decrease in environment tmeperature. The thermal energy around the metal plate decreases, also decreasing the kinetic energy.

4 0
2 years ago
21 mL It required 42.35 mL of H2SO4 to neutralize 21.17 mL of 0.5000 M NaOH. Calculate the concentration of H2SO4
bija089 [108]
The balanced equation for the above reaction is 
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of NaOH moles required-0.5000 M / 1000 mL/L x 21.17 mL = 0.010585 mol
According to stoichiometry, acid moles required are 1/2 of the base moles reacted
Therefore number of H₂SO₄ moles reacted - 0.010585 /2  mol
Number of moles in 42.35 mL of H₂SO₄ - 0.010585 /2 mol
Therefore in 1 L solution - (0.010585) /2 / 42.35 mL x 1000 mL/L = 0.125 M
Molarity of H₂SO₄ - 0.125 M
5 0
3 years ago
what is the strongest type of intermolecular forces present between a stearic acid molecule and a water molecule?
gtnhenbr [62]
Hydrogen bonding and dipole-dipole forces.
4 0
2 years ago
Nikolas, the fire extinguisher, and the skateboard have a combined mass of 50 kg. What force would the fire extinguisher have to
murzikaleks [220]

Answer:

Force used by fire extinguisher = 60 N

Explanation:

Given:

Mass of skateboard with fire extinguisher = 50 kg

Acceleration of fire extinguisher = 1.2 m/s²

Find:

Force used by fire extinguisher = ?

Computation:

⇒ Force = Mass × Acceleration

⇒ Force used by fire extinguisher = Mass of skateboard with fire extinguisher × Acceleration of fire extinguisher

⇒ Force used by fire extinguisher = 50 kg × 1.2 m/s²

⇒ Force used by fire extinguisher = 60 N

3 0
3 years ago
Read 2 more answers
Other questions:
  • A 9.780 -g gaseous mixture contains ethane (C2H6) and propane (C3H8). Complete combustion to form carbon dioxide and water requi
    8·1 answer
  • If given 5.98 x 10^24 atoms of Copper, how many kilograms do you have?
    11·1 answer
  • Terpin, prepared commercially by the acid-catalyzed hydration of limonene, is used medicinally as an expectorant for coughs. dra
    14·1 answer
  • What are three terms used to describe organisms such as cow
    11·1 answer
  • The starting pressure of a 15°C system was 1.50 atm. If the pressure rose to 1216 torr, what is the new temperature in Celsius?
    14·1 answer
  • A balloon at 32 °C is filled with 21 L of air. What would its volume be at a temperature of 52 °C, assuming pressure remains con
    5·1 answer
  • n the laboratory, two forms of sodium phosphate will be available (the monobasic monohydrate NaH2PO4·H2O, F.W. = 137.99 g/mol, a
    8·1 answer
  • Diatomic hydrogen gas and diatomic nitrogen gas react spontaneously to form a gaseous product. Give the balanced chemical equati
    8·2 answers
  • 3. Una piedra que se tira verticalmente hacia arriba se mueve según la
    12·1 answer
  • How many moles of oxygen atom are there in 0.5 moles of Ca(ClO3) 2?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!