If 0.97 moles of BaCl2 are dissolved in enough water to make a 1.2 liter soulution, what is the resulting molarity

1 answer:

5 0

If 1.2 L of solution contains 0.97 mol
then let 1 L of solution contain x mol

⇒ (1.2 L) x = (0.97 mol) (1 L)

x = (0.97 mol · L) ÷ (1.2 L)

x = 0.8083 mol

Thus the molarity of the Barium Chloride solution is 0.808 mol / L OR 0.808 mol/dm³.

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