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ch4aika [34]
4 years ago
13

If 0.97 moles of BaCl2 are dissolved in enough water to make a 1.2 liter soulution, what is the resulting molarity

Chemistry
1 answer:
Akimi4 [234]4 years ago
5 0
         If    1.2 L of solution contains 0.97 mol
then let     1 L of solution contain  x   mol
     
       ⇒ (1.2 L) x  = (0.97 mol) (1 L)

                      x  = (0.97 mol · L)  ÷  (1.2 L)

                      x  = 0.8083 mol

Thus the molarity of the Barium Chloride solution is 0.808 mol / L   OR  0.808 mol/dm³. 

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Gallium is produced by the electrolysis of a solution obtained by dissolving gallium oxide in concentrated NaOH(aq). Calculate t
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<u>Answer:</u> The mass of gallium produced by the electrolysis is 0.0354 grams.

<u>Explanation:</u>

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C=I\times t

where,

C = charge

I = current = 0.490 A

t = time required (in seconds) = 50\times 60=300s    (Conversion factor: 1 min = 60 s)

Putting values in above equation, we get:

C=0.490\times 300=147C

  • To calculate the moles of electrons, we use the equation:

\text{Moles of electrons}=\frac{C}{F}

where,

C = charge = 147 C

F = Faradays constant = 96500

\text{Moles of electrons}=\frac{147}{96500}=1.52\times 10^{-3}mol

  • Now, to calculate the moles of gallium, we use the equation:

\text{Moles of Gallium}=\frac{\text{Moles of electrons}}{n}

where,

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Putting values in above equation, we get:

\text{Moles of Gallium}=\frac{1.52\times 10^{-3}}{3}=5.077\times 10^{-4}mol

  • To calculate the mass of gallium, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of Gallium = 5.077\times 10^{-4}mol

Molar mass of Gallium = 69.72 g/mol

Putting values in above equation, we get:

5.077\times 10^{-4}mol=\frac{\text{Mass of Gallium}}{69.72g/mol}\\\\\text{Mass of Gallium}=0.0354g

Hence, the mass of gallium produced by the electrolysis is 0.0354 grams.

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