Question

If 0.97 moles of BaCl2 are dissolved in enough water to make a 1.2 liter soulution, what is the resulting molarity

Answer 1

         If    1.2 L of solution contains 0.97 mol
then let     1 L of solution contain  x   mol
     
       ⇒ (1.2 L) x  = (0.97 mol) (1 L)

                      x  = (0.97 mol · L)  ÷  (1.2 L)

                      x  = 0.8083 mol

Thus the molarity of the Barium Chloride solution is 0.808 mol / L   OR  0.808 mol/dm³.