Circle the term or phrase in parentheses that makes each statement true.
2 answers:
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Taking into account the reaction stoichiometry, the theoretical yield of oxygen when 29.2 g of water are decomposed by electrolysis is 25.956 grams.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
2 H₂O → 2 H₂ + O₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- H₂O: 2 moles
- H₂: 2 moles
- O₂: 1 mole
The molar mass of the compounds is:
- H₂O: 18 g/mole
- H₂: 2 g/mole
- O₂: 32 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- H₂O: 2 moles ×18 g/mole= 36 grams
- H₂: 2 moles ×2 g/mole= 4 grams
- O₂: 1 mole ×32 g/mole= 32 grams
The theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.
<h3>Theorical yield of O₂</h3>The following rule of three can be applied: if by reaction stoichiometry 36 grams of water form 32 grams of oxygen, 29.2 grams of water form how much mass of oxygen?
<u><em>mass of oxygen= 25.956 grams</em></u>
Finally, the theoretical yield of oxygen when 29.2 g of water are decomposed by electrolysis is 25.956 grams.
Learn more about the reaction stoichiometry:
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Answer:
1.08 g/L is the density of air.
Explanation:
Pressure of the gas = P (atm)
Volume of the gas = V (L)
Moles of gas = n =
Temperature of the gas = T (K)
where:
D = density of the gas =
R = universal gas constant
w = Mass of the gas
M =Molar mass of the gas
Given = P = 1.0 atm , T = 54°C = 327.15 K
Average molar mass of the gas = 29 g/mol
Putting all the given values in above equation.
D = 1.08 g/L
1.08 g/L is the density of air.
Given the molarity of the solution is.
The volume of the solution is 10.9/1000 L
Number of moles of HCl = Molarity * volume of the solution in L
Number of moles of HCl =*
Number of moles of HCl = 2.7 moles.
Therefore number of moles of HCl in 10.9 ml of the stomach acid is 2.7 moles