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3 years ago

I need help please please

Mathematics

2 answers:

Rudiy273 years ago

6 0

I think the answer to that is A

Katyanochek1 [597]3 years ago

4 0

9514 1404 393

Answer:

Step-by-step explanation:

The mnemonic SOH CAH TOA can remind you how to do this. It tells you ...

Sin = Opposite/Hypotenuse

Cos = Adjacent/Hypotenuse

Here, the hypotenuse XY is 12, so we expect to see answers with 12 in the denominator. Only choice C matches that.

We can confirm that choice by looking at the opposite side (YZ) to get ...

sin(X) = YZ/YX = √119/12

The cosine uses the adjacent side:

cos(X) = XZ/XY = 5/12

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HELP ASAP!!!!!! 34 ÷ (14 − 5) × 2

DIA [1.3K]

Answer:

Step-by-step explanation:

7 0

3 years ago

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A movie theater is holding a contest for people who are in line before 7 p.m. The people who are within eight places of the 99th

Doss [256]

Answer:

Step-by-step explanation:what is the answer for this question

4 0

3 years ago

Given T(x,y)=(x+5,y+4) and the point P(2,3), what is T(P)?

luda_lava [24]

<h3>Answer: (7, 7)</h3>

==============================================

Explanation:

T(P) is the notation applying the translation rule T(x,y) = (x+5, y+4) to the point P(2,3)

The x+5 means we add 5 to the x coordinate of P. We have x = 2 become x+5 = 2+5 = 7. The point P shifts 5 units to the right to go from (2,3) to (7,3)

Then the point shifts 4 units up to arrive at (7, 7). We shift 4 units up due to the y+4 in the translation rule.

Or put another way, y = 3 is the y coordinate of P. So y+4 = 3+4 = 7 is the new y coordinate.

4 0

3 years ago

Write each expression as a product of linear factors 1. X^2+1/2x 2. X^2+2x-3 3. (2x-3)^2 4. X^3+2x^2-19x-20

Grace [21]

Answer:

1. X^2+1/2x = $x(x+\frac{1}{2})$

2. X^2+2x-3 = $(x-1)(x+3)$

3. (2x-3)^2 = (2x-3)(2x-3)

4. X^3+2x^2-19x-20 = $(x+1)(x-4)(x+5)$

Step-by-step explanation:

Each expression can be written as a product of linear factors as follows

1. X^2+1/2x ⇒ $x^{2} + \frac{1}{2}x$

$x^{2} + \frac{1}{2}x$ = $x(x+\frac{1}{2})$

Hence, X^2+1/2x = $x(x+\frac{1}{2})$

2. X^2+2x-3 ⇒ $x^{2} +2x-3$

$x^{2} +2x-3 = x^{2} +3x-x-3$

$x^{2} +3x-x-3 = x(x+3) -1(x+3)$

$x(x+3) -1(x+3) = (x-1)(x+3)$

Hence, X^2+2x-3 = $(x-1)(x+3)$

3. (2x-3)^2 ⇒ $(2x-3)^{2}$

$(2x-3)^{2} = (2x-3)(2x-3)$

Hence, (2x-3)^2 = (2x-3)(2x-3)

4. X^3+2x^2-19x-20 ⇒ $x^{3}+2x^{2} -19x -20$

$x^{3}+2x^{2} -19x -20 = (x+1)(x^{2} +x-20)$

First,

$x^{2} +x-20 = x^{2} +5x-4x-20\\x^{2} +5x-4x-20= x(x+5)-4(x+5)\\x(x+5)-4(x+5) = (x-4)(x+5)$

∴ $(x+1)(x^{2} +x-20) = (x+1)(x-4)(x+5)$

Hence, X^3+2x^2-19x-20 = $(x+1)(x-4)(x+5)$

3 0

3 years ago

The angles in a triangle are in the ratio 1 : 2 : 3.

vekshin1

Answer:

yes

Step-by-step explanation:

6 0

3 years ago

I need help please please ​

I need help please please