I'm assuming a quarter-circle is exactly 1/4 of a circle. Thus if you have 4 congruent quarter-circles, that should mean they make a complete circle.
If that is the case, then we can find the area of the full circle using pi*r^2.
So the area of the circle is 5^2*pi or 25pi.
To find the area of the shaded region, we subtract the area of the circle from the area of the square.
The area of the square is 10^2 or 100.
So the area of the shaded region is 100 - 25pi.
My calculator says that equals roughly 21.46
Answer:
33/10 and 55/15
Step-by-step explanation:
Possible denominators that are multiples of 5 less than 17 are 5, 10, 15.
Corresponding numerator ranges are [15, 20], [30, 40], and [45, 60]. In only two of these ranges are there any multiples of 11.
33 in [30, 40]
55 in [45, 60]
So, there are only two possible fractions meeting your requirement:
33/10 and 55/15
True i think but i'm not postive
T(x, y) = (x - 5, y - 6) since you are trying to translate back to the original point and therefor should do the reverse set of translations
<u>Answer and explanation</u>
(1+sinθ)(1-sinθ)=cos²θ
We are to prove that the left hand side is equal to the right hand side.
(1+sinθ)(1-sinθ) = 1(1-sinθ) + sinθ(1-sinθ)
= 1 - sinθ + sinθ - sin²θ
= 1 - sin²θ
From the trigonometric identity sin²θ + cos²θ = 1,
1 - sin²θ = cos²θ
