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alexdok [17]
3 years ago
13

Out of every 40 pens, 5 pens are discarded. What percent of the pens are not discarded?

Mathematics
1 answer:
Gwar [14]3 years ago
3 0

87.5 percent

Reason: 40/40-5/40 is 35/40. Divide 35/40 and you get 0.875. Multiply by a hundred and you get 87.5%

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What is the quotient of the synthetic division problem below, written in polynomial form?
Alex17521 [72]

Answer:

<em>The answer is (B)</em>

Step-by-step explanation:

6 0
2 years ago
Find the distance between the points (5, -5) and (-7,4).
abruzzese [7]

Answer:

<h2>The answer is 15 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  } \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(5, -5) and (-7,4)

The distance between them is

d =  \sqrt{ ({5 + 7})^{2}  +  ({ - 5 - 4})^{2} }  \\  =  \sqrt{ {12}^{2}  + ( { - 9})^{2} }  \\  =  \sqrt{144 + 81}  \\  =  \sqrt{225}  \\  = 15 \:  \:  \:  \:  \:  \:

We have the final answer as

<h3>15 units</h3>

Hope this helps you

4 0
3 years ago
Historically, the proportion of people who trade in their old car to a car dealer when purchasing a new car is 48%. Over the pre
choli [55]

Answer:

z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.  

Step-by-step explanation:

Data given and notation

n=115 represent the random sample taken

X=46 represent the number of people that have traded in their old car.

\hat p=\frac{46}{115}=0.4 estimated proportion of people that have traded in their old car

p_o=0.48 is the value that we want to test

\alpha=0.1 represent the significance level

Confidence=90% or 0.9

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.48.:  

Null hypothesis:p\geq 0.48  

Alternative hypothesis:p < 0.48  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.4 -0.48}{\sqrt{\frac{0.48(1-0.48)}{115}}}=-1.717  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.1. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

So the p value obtained was a very low value and using the significance level given \alpha=0.1 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.  

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Answer: 84 is your answer hope this helped

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Step-by-step explanation:

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