How do I solve -4(7a+5)=-160

2 answers:

8 0

you distribute -4 into 7a+5 making it -28a-20=-160 add 20 on both sides -160+20=-140 then divide -28 to -140 making a=5

valina [46]3 years ago

6 0

-4(7a+5)=-160

-28a-20=-160 multiply through by -4

-28a=-160+20 add 20 to both sides

-28a=-140

a=-140/-28 divide both sides by -28

a= 5

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Kavi solved the system

Marianna [84]

Answer:

She should have substituted y = 17 - 2x in the first equation

Step-by-step explanation:

3x + 4y = 33

2x + y = 17

y = 17 - 2x

3x + 4(17 - 2x) = 33

3x + 68 - 8x = 33

5x = 35

x = 7

y = 17 - 2(7)

y = 3

x = 7, y = 3

Only one solution

6 0

4 years ago

Factor completely, the expression: 2x^3-2x^2-12x

muminat

$2x^3-2x^2-12x=2x(x^2-x-6)=(*)\\\\------------------------------\\x^2-x-6\\\\a=1;\ b=-1;\ c=-6\\\\\Delta=(-1)^2-4\cdot1\cdot(-6)=1+24=25\\\\\sqrt\Delta=\sqrt{25}=5\\\\x_1=\frac{1-5}{2\cdot1}=\frac{-4}{2}=-2;\ x_2=\frac{1+5}{2\cdot1}=\frac{6}{2}=3\\\\x^2-x-6=(x+2)(x-3)\\\\------------------------------\\\\(*)=2x(x+2)(x-3)$