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vagabundo [1.1K]

4 years ago

15

If two charged objects are moved closer to each other, the electric force between them will?

1 answer:

snow_tiger [21]4 years ago

6 0

Get stronger that’s the answer hopefully

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against at -20 degree centigrade occupied the volume of one 40 ml calculate the temperature at which the volume of cash pickup 6

worty [1.4K]

The final temperature :T₂=411.125 K = 138.125 °C

<h3>Further explanation</h3>

Given

T₁=-20 °C+273 = 253 K

V₁=40 ml

V₂=65 ml

Required

Final temperature

Solution

Charles's Law

When the gas pressure is kept constant, the gas volume is proportional to the temperature

$\tt \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}$

Input the value :

T₂=(V₂.T₁)/V₁

T₂=(65.253)/40

T₂=411.125 K = 138.125 °C

4 0

3 years ago

A certain substance X condenses at a temperature of 123.3 degree C . But if a 650. g sample of X is prepared with 24.6 g of urea

Pavel [41]

Answer:

<u>The molal boiling point elevation constant is 1.59 ≈ 1.6</u> $Kkgmol^{-1}$

Explanation:

To solve this question , we will make use of the equation ,

Δ $T_{b} = i*K_{b} *m$

<em>where , </em>

<em>Δ $T_{b}$ is the change in boiling point of the substance $X$ ( ° $C$ or $K$ )</em>

<em> $i$ is the Vant Hoff Factor which = 1 in this case ( no unit )</em>

<em> $K_{b}$ is the mola boiling point elevation constant of X ( $Kkgmol^{-1}$ )</em>

<em> $m$ is the molality of the solution which has $(NH_{2})_{2} CO$ as the solute and $X$ as the solution ( $molkg^{-1}$ )</em>

Δ $T_{b}$ = $124.3 -123.3 = 1$ ° $C$ or $K$ ;
$i$ =1;
$m$ = $\frac{moles of solute}{weight of solvent(kg)}$ $molkg^{-1}$

∴ $m = \frac{\frac{24.6}{60} }{\frac{650}{1000} }$

<em>as the weight of $(NH_{2})_{2} CO$ is $60g$ and thus number of moles = $\frac{24.6}{60}$ </em>

<em>and the weight of solvent in $kg$ is $\frac{650}{1000}$ </em>

4. $K_{b}$ ⇒ ?

∴

$1=1*K_{b} *\frac{\frac{24.6}{60} }{\frac{650}{1000} }$

⇒ $K_{b}$ = $1.59$ ≈ 1.6 $Kkgmol^{-1}$

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3 years ago

Please help I can't balance and Google isn't helping

DiKsa [7]

The first one is right and so is eight you have to add them together to see if they go together if they dont add what is missing

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3 years ago

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liubo4ka [24]

Answer:

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3 years ago

Read 2 more answers

Calculate the mass of 0. 4 moles of water.

Anna [14]

Answer:

7.208 g

Explanation:

0.4mol x $\frac{2(1.01) + 16.00 g}{1 mol}$

= 7.208 g

You are using molar mass of H20 to find the mass. Moles of 0.4 and 1 mol cancel out leaving you with just grams. You get the values in the numerator from the periodic table and the 2(1.01) is because you have 2 of the H in H20

5 0

3 years ago