If we are to draw the sulfuric acid structure based on
Lewis it would look like:
O
ll
O =
S – O –H
l
O
l
H
So from this, we can see that there are 2 double bonds (O
= S) and 4 single bonds (S – O and O – H).
Therefore the answer is:
4 single, 2 double
Answer:
= 3/4
Explanation:
Half life is the time taken by a radioactove element to decay by half of its original mass.
The half life of tritium is 12.3 years , therefore it would take 12.3 years for tritium to decay to a half its original mass.
Using the formula;
New mass = Initial mass × (1/2)^n ; where n is the number of half lives.
n = 5.2 years/12.3 years
= 52/123
Therefore;
New mass = 1 × (1/2)^(52/123)
= 0.74599
= 0.75
The fraction of a tritium sample after 5.20 years will be approximately 3/4
Answer:
0.3267 M
Explanation:
To solve this problem, first we calculate how many moles of Mn(ClO₄)₂ are contained in 23.640 g of Mn(ClO₄)₂·6H₂O.
Keep in mind that the crystals of Mn(ClO₄)₂ are hydrated, and <em>we need to consider those six water molecules when calculating the molar mass of the crystals</em>.
Molar mass of Mn(ClO₄)₂·6H₂O = 54.94 + (35.45+16*4)*2 + 6*18 = 361.84 g/mol
Now we <u>proceed to calculate</u>:
- 23.640 g Mn(ClO₄)₂·6H₂O ÷ 361.84 g/mol = 0.0653 mol Mn(ClO₄)₂·6H₂O = mol Mn(ClO₄)₂
Now we divide the moles by the volume, to <u>calculate molarity</u>:
- 200 mL⇒ 200/1000 = 0.200 L
- 0.0653 mol Mn(ClO₄)₂ / 0.200 L = 0.3267 M
Answer:
first of all is that really chemistry
