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seropon [69]
3 years ago
14

Hypothetical element X has 3 stable isotopes. The relative peak intensities are 79.52 for 180.0 u, 100.0 for 184.0 u, and 82.98

for 186.0 u. What is the average atomic mass for X
Chemistry
1 answer:
vazorg [7]3 years ago
3 0

Answer:

The relative atomic mass of X is 183.4

Explanation:

The relative atomic mass of an element is the weighted average of the masses of the isotopes using the carbon-12 atom has a mass of exactly 12 units as as a standard.

The relative sizes of the peaks gives a direct measure of the relative abundances of the isotopes. The tallest peak is often given an arbitrary height of 100 and is known as the base peak.

To calculate the relative atomic mass of the element X which has 3 stable isotopes with the relative peak intensities as given below:

79.52 for 180.0 u, 100.0 for 184.0 u, and 82.98 for 186.0 u, the sum of the products of the relative peak intensity of each isotope and their isotopic mass is divided by the sum of the peak intensities.

Relative atomic mass of X = (79.52 × 180) + (100 × 184.0) + (82.98 × 186)/(79.52 + 100 + 82.98)

Relative atomic mass of X = (14313.6 + 18400 + 15434.28)/(262.5)

Relative atomic mass of X = 48147.88/262.5 = 183.4

Therefore, the relative atomic mass of X is 183.4

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Why is earth’s interior layered?
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0.265g of an organic compound produced an evaporation 102cm³ of vapour at 373k and 775mmHg percentage composition of the constit
kumpel [21]

A. The molecular mass of the compound is 77.9 g/mol

B. The molecular formula of the compound is C₆H₆

<h3><u>Determination of the mole of the compound</u></h3>

We'll begin by calculating the number of mole of compound using the ideal gas equation as shown below:

  • Volume (V) = 102 cm³ = 102 / 1000 = 0.102 L
  • Temperature (T) = 373 K
  • Pressure (P) = 775 mmHg = 775 / 760 = 1.02 atm
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Number of mole (n) =?

n = PV / RT

n = (1.02 × 0.102) / (0.0821 × 373)

n = 0.0034 mole

<h3><u>A.</u><u> Determination of the </u><u>molecular mass</u><u> of the </u><u>compound</u><u>. </u></h3>
  • Mass = 0.265 g
  • Number of mole = 0.0034 mole
  • Molecular mass =?

Molecular mass = mass / mole

Molecular mass = 0.265 / 0.0034

Molecular mass of compound = 77.9 g/mol

<h3><u>B</u><u>. Determination of the </u><u>molecular formula</u><u> of the compound. </u></h3>

We'll begin by calculating the empirical formula of the compound.

  • Carbon (C) = 92.24%
  • Hydrogen (H) = 7.76%

Empirical formula =?

Divide by their molar mass

C = 92.24 / 12 = 7.69

H = 7.76 / 1 = 7.76

Divide by the smallest

C = 7.69 / 7.69 = 1

H = 7.76 / 7.69 = 1

Thus the empirical formula of the compound is CH

Finally, we shall determine the molecular formula.

  • Molecular mass = 77.9 g/mol
  • Empirical formula = CH
  • Molecular formula =?

Molecular formula = empirical × n = molecular mass

[CH]n = 77.9

[12 + 1]n = 77.9

13n = 77.9

Divide both side by 13

n = 77.9 / 13

n = 6

Molecular formula = [CH]n

Molecular formula = [CH]₆

Molecular formula = C₆H₆

Complete Question:

0.265g of an organic compound produced on evaporation 102cm cube of vapour at 373K and 775mmHg. Percentage composition of the constituent elements are 92.24% C and 7.76% H. Find the molecular mass and molecular formula of the composition.

Learn more about ideal gas equation:

brainly.com/question/14364992

Learn more about molecular formular:

brainly.com/question/512891

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