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4 years ago

If I add 475mL of water to 75.0mL of a 0.315M NaOH solution, what will the molarity of the diluted solution be?

1 answer:

5 0

Answer is: <span>the molarity of the diluted solution 0,043 M.
</span>V(NaOH) = 75 mL ÷ 1000 mL/L = 0,075 L.
c(NaOH) = 0,315 M = 0,315 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,075 L · 0,315 mol/L.
n(NaOH) = 0,023625 mol.
V(solution) = 0,475 L + 0,75 L.
c(solution) = 0,023625 mol ÷ 0,550 L.
c(solution) = 0,043 mol/L.

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4 years ago

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$\text{Moles of }CuSO_4=0.113mol/L\times 0.0406L=0.00459mol$

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Total moles copper(II) ion = 0.00459 mol + 0.00869 mol

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Thus, the final concentration of copper(II) ion is, 0.198 M

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3 years ago