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3 years ago

The decomposition of dinitrogen tetraoxide into nitrogen gas and oxygen gas is shown by which balanced chemical equation?

1 answer:

6 0

Know what decomposition is. The compound is "breaking down".

Di means 2 while, Tetra means 4.

First, we will simply follow the instructions and break down the compound as so: The decomposition of dinitrogen tetraoxide into nitrogen gas and oxygen gas

*Take into account that diatomic molecules (HNOFClBRI) will always have a subscript of 2

N₂O₄⇒N₂+O₂

After breaking down the compound, we must now balance the equation.

To balance the equation, we must make sure that each element has the same amount of atoms.

Starting with compound at the left of the yield: N=2 and O=4
But, at the right of the yield: N=2 and O=2
We have now discovered that the oxygen gas is not balanced throughout the equation.

N₂O₄⇒N₂+2O₂

*We simply multiply the oxygen gas on the right of the equation by 2

After multiplying, on the right side of the equation, O=4. We now have a balanced equation because all elements have the same amount of atoms on each side.

So your final answer for this balanced decomposition chemical equation is: N₂O₄⇒N₂+O₂

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A sample of gas (1.9 mol) is in a flask at 21 °C and 697 mm Hg. The flask is opened and more gas is added to the flask. The new

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Answer: There are now 2.07 moles of gas in the flask.

Explanation:

$PV=nRT$

P= Pressure of the gas = 697 mmHg = 0.92 atm (760 mmHg= 1 atm)

V= Volume of gas = volume of container = ?

n = number of moles = 1.9

T = Temperature of the gas = 21°C=(21+273)K= 294 K (0°C = 273 K)

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When more gas is added to the flask. The new pressure is 775 mm Hg and the temperature is now 26 °C, but the volume remains same.Thus again using ideal gas equation to find number of moles.

$PV=nRT$

P= Pressure of the gas = 775 mmHg = 1.02 atm (760 mmHg= 1 atm)

V= Volume of gas = volume of container = 49.8 L

n = number of moles = ?

T = Temperature of the gas = 26°C=(26+273)K= 299 K (0°C = 273 K)

R= Value of gas constant = 0.0821 Latm\K mol

$n=\frac{PV}{RT}=\frac{1.02\times 49.8}{0.0821\times 299}=2.07moles$

Thus the now the container contains 2.07 moles.

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