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levacccp [35]
3 years ago
9

The pOH of a solution is 9.21. Calculate the hydrogen ion concentration of the solution. Be sure to report your answer to the co

rrect number of significant figures
Chemistry
1 answer:
11Alexandr11 [23.1K]3 years ago
3 0

Answer:

[OH-] = 6.17 *10^-10

Explanation:

Step 1: Data given

pOH = 9.21

Step 2: Calculate [OH-]

pOH = -log [OH-] = 9.21

[OH-] = 10^-9.21

[OH-] = 6.17 *10^-10

Step 3: Check if it's correct

pOH + pH = 14

[H+]*[OH-] = 10^-14

pH = 14 - 9.21 = 4.79

[H+] = 10^-4.79

[H+] = 1.62 *10^-5

6.17 * 10^-10 * 1.62 * 10^-5 = 1* 10^-14

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Answer:

11.3 g/mL.

Explanation:

  • Density is a characteristic property of a substance.
  • The density of a substance is the relationship between the mass of the substance and the volume it takes up.

<em>d = m/V,</em>

where, d is the density of the metal,

m is the mass of the metal (m = 12.475 g),

V is the volume that the metal takes up (V = 6.1 mL - 5.0 mL = 1.1 mL).

<em>∴ d = m/V =</em> (12.475 g)/(1.1 mL) = <em>11.34 g/mL ≅ 11.3 g/mL.</em>

<em>The significant figures has its rules in the calculations; the result has a significant figures to the lowest no. of significant figures (1.1 has two significant figures, while 12.475 has 5 significant figures), so the result should have only 2 significant figures.</em>

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BaO2(s) + 2HCl(aq) → H2O2(aq) + BaCl2(aq) What mass of hydrogen peroxide should result when 1.50 g barium peroxide is treated wi
Solnce55 [7]

Answer:

mass H2O2 = 0.31g H2O2

mass unreacted = 0.0745g BaO2

Explanation:

Mw BaO2 = 169.33 g / mol

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Mw H2O2 = 34.0147 g/mol

LR:

⇒ mol BaO2 = 1.50g BaO2 * mol / 169.33 g = 8.86E-3 mol BaO2 / 1 = 8.86E-3 mol BaO2

⇒ mol HCl = 25.0 mL * 0.0272g / mL * mol / 36.46g = 0.0186 mol HCl / 2 = 9.3E-3 mol HCl.....L.R

mol H2O2:

⇒ 0.0186mol HCl * (mol H2O2 / 2mol HCl) = 9.325E-3 mol H2O2

⇒ g H2O2 = 9.325E-3mol H2O2 * 34.0147g H2O2 / mol H2O2 = 0.31g H2O2

mass of wich reagent is left unreacted:

mol that react BaO2 = 0.0186mol HCl * (mol BaO2 / 2mol HCl) = 9.3E-3mol BaO2

mol that unreacted BaO2 = 9.3E-3 - 8.86E-3 = 4.4E-4 mol BaO2

g unreacted BaO2 = 4.4E-4mol BaO2 * (169.33g BaO2 / mol BaO2) = 0.0745g BaO2

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3 years ago
Mrs. Vikram's science class notices that a high
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Storm clouds being formed will most likely occur in this scenario.

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We were told that the weather is warm and cold air will enter the region which means that it will replace the heat and moisture as they move upwards thereby resulting in the formation of storm clouds.

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