Smell of berium please answer fast

Introduction: Chemical formulas represent ratios. To make H2O, you need two atoms of H for each atom of O; you would also need t

Nina [5.8K]

Answer:

The answer to your question is given below

Explanation:

To convert from Particles to grams, one must have a clear understanding of Avogadro's hypothesis. From the Avogadro's hypothesis, we can easily convert from mole to particles and to grams.

Avogadro's hypothesis gives us a background understanding that 1 mole of any substance contains 6.02x10^23 particles. With this in mind we can easily convert particles to grams and grams to particles.

Now consider the following example:

1. How many particles are there in 4g of carbon?

Solution:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 particles. This implies that 1 mole of carbon contains 6.02x10^23 particles.

1 mole of carbon = 12g

Now we can say that 12g of carbon contains 6.02x10^23 particles.

If 12g of carbon contains 6.02x10^23 particles,

then 4g of carbon will contain = (4x6.02x10^23) /12 = 2.01x10^23 particles.

The next example will teach us how to convert from particles to grams..

2. What mass of helium contains 4.2x10^24 particles.

Solution:

According to Avogadro's hypothesis,

1 mole of He contains 6.02x10^23 particles.

1 mole of He = 4g

We can thus, say that 4g of He contains 6.02x10^23 particles.

1f 4g of He contains 6.02x10^23 particles,

Then Xg of He contains 4.2x10^24 Particles i.e

Xg of He = (4x4.2x10^24)/(6.02x10^23)

Xg of He = 27.91g

Therefore, 27.91g of He contains 4.2x10^24 Particles

With the above illustrations I believe you have understood how to convert from grams to particles and from particles to grams.

7 0

3 years ago

NEED HELP ASAP! Figure out which one is what! Answer choices at bottom!

valkas [14]

Conduction
2
4
7

Convection
1
8
9
10

Radiation
3
5
6

3 0

3 years ago

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Balance the following redox reaction in basic solution. Cl â’ (aq) + MnO â’ 4 (aq) â†’ Cl 2 (g) + MnO 2 (s)

FinnZ [79.3K]

$6\; \text{Cl}^{-} \; (aq) + 2\; \text{MnO}_4^{-} \; (aq) + 4 \; \text{H}_2 \text{O} \; (l) \to 3\; \text{Cl}_2 \; (g) + 2\; \text{MnO}_2 \; (s) + 8\; \text{OH}^{-} \; (aq)$

<h3>Explanation</h3>

The oxidation state of the manganese atom $\text{Mn}$ changes from +7 as in $\text{MnO}_4^{-}$ to +4 as in $\text{MnO}_2$ .
There are one $\text{Mn}$ atom in each $\text{MnO}_4$ ion.
Reducing each $\text{MnO}_4^{-}$ ion would thus consume three electrons.

Similarly, the oxidation state of the chlorine atom $\text{Cl}$ changes from -1 as in $\text{Cl}^{-}$ to 0 as in $\text{Cl}_2$ .
It takes two $\text{Cl}^{-}$ ions to produce one $\text{Cl}_2$ molecule.
Oxidizing every two $\text{Cl}^{-}$ would thus produce one $\text{Cl}_2$ while releasing two electrons.

Three $\text{Cl}_2$ molecules contain six chlorine atoms. Three $\text{Cl}_2$ would thus correspond to six $\text{Cl}^{-}$ ions.

Combining six $\text{Cl}^{-}$ , two $\text{MnO}_4^{-}$ ions, three $\text{Cl}_2$ ions, and two $\text{MnO}_2$ would balance the changes in oxidation state.

$6\; \text{Cl}^{-} \; (aq) + 2\; \text{MnO}_4^{-} \; (aq) \to 3\; \text{Cl}_2 \; (g) + 2\; \text{MnO}_2 \; (s)$ (NOT BALANCED)

Still, the product side lacks four oxygen atoms.

In an acidic environment, oxygen atoms would combine with protons to produce water.
In a basic environment (like this one,) there are nearly no protons for oxygen atoms to combine with. Oxygen atoms will likely combine with water to produce hydroxide ions.

Each oxygen atom combine with a water molecule to produce two hydroxide ions. Adding four water molecules and eight hydroxide ions would balance the equation.

5 0

3 years ago

Write the reaction for breaking all the bonds in c6h6(g).

Usimov [2.4K]

Hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

3 0

3 years ago

How many orbitals are in the n=3 level

solniwko [45]

The third shell has 3 subshells: the subshell, which has 1 orbital with 2 electrons, the subshell, which has 3 orbitals with 6 electrons, and the subshell, which has 5 orbitals with 10 electrons, for a total of 9 orbitals and 18 electrons.

7 0

3 years ago

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