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Ivenika [448]
4 years ago
13

Assuming that the smallest measurable wavelength in an experiment is 0.650 fm (femtometers), what is the maximum mass of an obje

ct traveling at 129 m·s–1 for which the de Broglie wavelength is observable?
Chemistry
1 answer:
yKpoI14uk [10]4 years ago
6 0

Hey there!:

Wavelength λ = 0.650 fm = 0.650* 10⁻¹⁵ m (1 fm = 10⁻¹⁵ m)

Speed v = 129 m/s⁻¹

Planck constant h = 6.626 * 10⁻³⁴ J.s

De Broglie equation: λ = h/mv

Mass m = h/λv

= 6.626 * 10⁻³⁴/ ( 0.650* 10⁻¹⁵ * 129)

= 6.626*10⁻³⁴ / 8.385*10⁻¹⁴

= 7.902*10⁻²¹ Kg


Hope that helps!

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Naoki's bicycle has a mass of 10 kg. If Naoki sits on her bicycle and starts pedaling with a force of 168 N, causing an accelera
White raven [17]

Answer:

50 kg

Explanation:

Data:

Mass of bicycle = 10 kg

                       F = 168 N

                       a = 2.8 m/s²

Calculation:

                     F = ma     Divide each side by m, Then

                 m = F/a

                     = 168/2.8

                      = 60 kg

                 m = mass of bicycle + Naoki's mass. Then

                60 = 10 + Naoki's mass     Subtract 10 from each side

Naoki's mass = 50 kg

3 0
3 years ago
What is the limiting reagent when a 2.00 g sample of ammonia is mixed with 4.00 g of oxygen?​
UNO [17]

Answer:

Ammonia is limiting reactant

Amount of oxygen left  = 0.035 mol

Explanation:

Masa of ammonia = 2.00 g

Mass of oxygen = 4.00 g

Which is limiting reactant = ?

Balance chemical equation:

4NH₃ + 3O₂     →     2N₂ + 6H₂O

Number of moles of ammonia:

Number of moles = mass/molar mass

Number of moles = 2.00 g/ 17 g/mol

Number of moles = 0.12 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 4.00 g/ 32 g/mol

Number of moles = 0.125 mol

Now we will compare the moles of ammonia and oxygen with water and nitrogen.

                      NH₃          :            N₂

                        4             :             2

                      0.12           :           2/4×0.12 = 0.06

                      NH₃         :            H₂O

                        4            :             6

                        0.12       :           6/4×0.12 = 0.18

                       

                       O₂            :            N₂

                        3             :             2

                      0.125        :           2/3×0.125 = 0.08

                        O₂           :            H₂O

                        3              :             6

                        0.125       :           6/3×0.125 = 0.25

The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.

Amount of oxygen left:

                        NH₃          :             O₂

                           4            :              3

                           0.12       :          3/4×0.12= 0.09

Amount of oxygen react = 0.09 mol

Amount of oxygen left  = 0.125 - 0.09 = 0.035 mol

3 0
3 years ago
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1) Which of the following is true about Earth’s plates?
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Answer:

a because the others whould cause earthquakes

Explanation:

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When 12 moles of o2 react with 1.1 mole of c10h8 what is the limiting reactant?
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1.1   moles   of C10H8  is the  limiting  reagent  in   the  reaction between   reaction  C10H8   and   O2
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3 years ago
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