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Ivenika [448]
4 years ago
13

Assuming that the smallest measurable wavelength in an experiment is 0.650 fm (femtometers), what is the maximum mass of an obje

ct traveling at 129 m·s–1 for which the de Broglie wavelength is observable?
Chemistry
1 answer:
yKpoI14uk [10]4 years ago
6 0

Hey there!:

Wavelength λ = 0.650 fm = 0.650* 10⁻¹⁵ m (1 fm = 10⁻¹⁵ m)

Speed v = 129 m/s⁻¹

Planck constant h = 6.626 * 10⁻³⁴ J.s

De Broglie equation: λ = h/mv

Mass m = h/λv

= 6.626 * 10⁻³⁴/ ( 0.650* 10⁻¹⁵ * 129)

= 6.626*10⁻³⁴ / 8.385*10⁻¹⁴

= 7.902*10⁻²¹ Kg


Hope that helps!

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Gennadij [26K]

Answer:

the terminator because i did this test

5 0
3 years ago
Suppose that you use a pair of chopsticks and apply a force of 1 N over a distance of 0.01 m. How much work do you do? If the ou
Leto [7]

Explanation:

Work done = force * perpendicular distance

= 1 * 0.01 = 0.01 joules

7 0
3 years ago
You are preparing some solutions for your instructor and have been asked to prepare 3.00 L of a 0.250M sodium hydroxide solution
grigory [225]

Answer:

C. 30.0 g NaOH and add water until the final solution has a volume of 3.00 L.

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

from the question ,

M =  0.250M

V  = 3.00 L

M = n / V

n = M * v

n = 0.250M * 3.00 L = 0.75 mol

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

n = 0.75 mol NaOH

m = molecular mass of NaOH = 40 g/mol

n = w / m

w = n * m

w = 0.75 mol * 40 g/mol = 30.0 g

Hence , by using 30.0 g of NaOH and dissolving it to make up the volume to 3 L , a solution of 0.250 M can be prepared .

4 0
3 years ago
Red blood cells are formed in the bone marrow of the _______
Lostsunrise [7]
Red blood cells are formed in the red bone marrow of bones. Stem cells in the red bone marrow called hemocytoblasts give rise to all of the formed elements in blood. If a hemocytoblast commits to becoming a cell called a proerythroblast, it will develop into a new red blood cell.
6 0
3 years ago
What is the boiling point of a sample of Propanone at 180kpa?
shepuryov [24]

Answer: The boiling point of a sample of Propanone at 180 kPa is 75 C. The correct answer is 2.

Explanation:

Propanone is more commonly known under the name "acetone." The boiling point of this compound at 180 kPa will be 75 C. It is an organic compound and its formula is (CH3)2CO.

This compound does not any color, it is highly flammable, and volatile. This compound does have a distinguished odor. It is used in labs, in industry settings, and in the home for various things. The human body does produce this compound naturally and the body disposes of this compound.

3 0
3 years ago
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