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3 years ago

What is the boiling point of a sample of Propanone at 180kpa?

Chemistry

1 answer:

shepuryov [24]3 years ago

3 0

Answer: The boiling point of a sample of Propanone at 180 kPa is 75 C. The correct answer is 2.

Explanation:

Propanone is more commonly known under the name "acetone." The boiling point of this compound at 180 kPa will be 75 C. It is an organic compound and its formula is (CH3)2CO.

This compound does not any color, it is highly flammable, and volatile. This compound does have a distinguished odor. It is used in labs, in industry settings, and in the home for various things. The human body does produce this compound naturally and the body disposes of this compound.

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When naming a transition metal ion that can have more than one common ionic charge, the numberical value of the charge can be in

Ivenika [448]

Answer: C) Roman numeral following the name.

Explanation: If we want to name an ionic compound like NaCl then we can easily write its name. Na is sodium and Cl is chlorine. First we write the name of the metal ion and then the name of the anion it has. Here we have mono atomic ion and for these we use the suffix -ide. So, the name will be sodium chloride.

Now, if we have something like $FeCl_3$ and we write the name as Iron chloride, then it will not be correct since Fe is a transition metal and it shows +2 and +3 oxidation states. So, to overcome this difficulty, a roman numeral is used for the oxidation state of the metal ion. The name of above compound will be Iron(III)chloride. Similarly, if we have $FeCl_2$ then its name will be written as Iron(II)chloride.

In both the above names, the roman numerals (III) and (II) are indicating numerical value of the charge of the metal ion. So, the correct choice is C) Roman numerals following the name.

when naming a transition metal ion that can have more than one common ionic charge, the numerical value of the charge can be indicated by a Roman numeral following the name.

8 0

4 years ago

Sodium combines with water to produce sodium hydroxide and hydrogen gas. Which word equation represents this violent reaction?

Natalka [10]

Answer: sodium + water → sodium hydroxide + hydrogen

Explanation:

1) The first part of the statment "sodium combines with water" means that these two pure substances are the reactants.

Sodium is an alkali metal (group 1: Li, Na, K, Rb, Cs, Fr).

A typical chemical property of the alkali metal elments is that they react violently with water fo form the corresponding hydroxide and hydrogen gas.

2) The next two words, "to produce ". indicates, precisely, that what follow is the product of the reaction. In the chemical reaction it is indicated by the arrow →

3) Finally, you are told the products of the reaction: sodium hydroxide and hydrogen gas.

4) The word equation then follows the order reactants → products, which in this case is the sodium + water → sodium hydroxide + hydrogen

5) Using chemical symbols and conventions, that is:

Na(s) + H₂O (l) → NaOH(aq) + H₂(g).

5 0

3 years ago

Read 2 more answers

Silver nitrate bond type

SVEN [57.7K]

Silver nitrate is an ionic bond because it is made up of metal, sliver, and a non-metal, nitrogen and oxygen. It is also a polyatomic ion (you only find polyatomic ions in ionic bonds).

4 0

3 years ago

Which equation was used by Albert Einstein to explain the photoelectric effect? [E = energy, h = Planck’s constant, and v = freq

devlian [24]

Answer:

E = hV

Explanation:

Hello,

Photo electric effect theory was borne out the the confusing if light was either a particle or a wave. However Albert Einstein came up with a theory that light was a particle and each particle carry a certain amount of energy referred to as photons.

He used Max Planck's idea and theorized that since light is made up of photon, when each photon comes in contact with the surface of a metal, the energy is transferred to the electron.

E = hv

E = energy of the photons

h = Planck's constant = 6.626×10⁻³⁴Js

v = frequency of the photon in Hz

4 0

3 years ago

Find the mass of 3.27 x 10^23 molecules of H2SO4. Use 3 significant digits<br> and put the units.

marta [7]

Answer:

Approximately $53.3\; \rm g$ .

Explanation:

Lookup Avogadro's Number: $N_{\rm A} = 6.02\times 10^{23}\; \rm mol^{-1}$ (three significant figures.)

Lookup the relative atomic mass of $\rm H$ , $\rm S$ , and $\rm O$ on a modern periodic table:

$\rm H$ : $1.008$ .
$\rm S$ : $32.06$ .
$\rm O$ : $15.999$ .

(For example, the relative atomic mass of $\rm H$ is $1.008$ means that the mass of one mole of $\rm H\!$ atoms would be approximately $1.008\!$ grams on average.)

The question counted the number of $\rm H_2SO_4$ molecules without using any unit. Avogadro's Number $N_{\rm A}$ helps convert the unit of that count to moles.

Each mole of $\rm H_2SO_4$ molecules includes exactly $(1\; {\rm mol} \times N_\text{A}) \approx 6.02\times 10^{23}$ of these $\rm H_2SO_4 \!$ molecules.

$3.27 \times 10^{23}$ $\rm H_2SO_4$ molecules would correspond to $\displaystyle n = \frac{N}{N_{\rm A}} \approx \frac{3.27 \times 10^{23}}{6.02 \times 10^{23}\; \rm mol^{-1}} \approx 0.541389\; \rm mol$ of such molecules.

(Keep more significant figures than required during intermediary steps.)

The formula mass of $\rm H_2SO_4$ gives the mass of each mole of $\rm H_2SO_4\!$ molecules. The value of the formula mass could be calculated using the relative atomic mass of each element:

$\begin{aligned}& M({\rm H_2SO_4}) \\ &= (2 \times 1.008 + 32.06 + 4 \times 15.999)\; \rm g \cdot mol^{-1} \\ &= 98.702\; \rm g \cdot mol^{-1}\end{aligned}$ .

Calculate the mass of approximately $0.541389\; \rm mol$ of $\rm H_2SO_4$ :

$\begin{aligned}m &= n \cdot M \\ &\approx 0.541389\; \rm mol \times 98.702\; \rm g \cdot mol^{-1}\\ &\approx 53.3\; \rm g\end{aligned}$ .

(Rounded to three significant figures.)

6 0

3 years ago