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trapecia [35]
3 years ago
8

Suppose that you use a pair of chopsticks and apply a force of 1 N over a distance of 0.01 m. How much work do you do? If the ou

tput force of the chopsticks is only 0.5 N, how far do the tips of the chopsticks move?
Chemistry
1 answer:
Leto [7]3 years ago
7 0

Explanation:

Work done = force * perpendicular distance

= 1 * 0.01 = 0.01 joules

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What does the prefix trans-indicate?
kogti [31]

Answer: I think trans- prefix Definition of trans- (Entry 3 of 3) 1 : on or to the other side of : across : beyond transatlantic. 2a : beyond (a specified chemical element) in the periodic table transuranium

Explanation:

The prefix trans- and its variant tra-, which mean “across,” appear in many English vocabulary words, for example: transmit, transform, and trajectory. Consider the word translation, which is the carrying “across” from one language into another.

Hope it helps

5 0
3 years ago
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PLEASE HELP WILL MARK BRAINLIEST!
garik1379 [7]

Answer:

Pure substances are further broken down into elements and compounds. Mixtures are physically combined structures that can be separated into their original components. ... A heterogeneous mixture is a mixture of two or more chemical substances where the various components can be visually distinguished.

Explanation:

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3 years ago
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A voltaic cell is constructed from an Ni2+(aq)−Ni(s) half-cell and an Ag+(aq)−Ag(s) half-cell. The initial concentration of Ni2+
SCORPION-xisa [38]

Explanation:

For what I can see, is missing the concentration of [Ag+] in the half-cell. To calculate it:

Niquel half-cell

Oxidation reaction: Ni \longrightarrow Ni^{2+}+2 e^-

E=E^0 - \frac{R*T}{n*F}*ln(1/[Ni^{2+}])

Assuming T=298 K / R=8.314 J/mol K / F=96500 C

E=-0.23V - \frac{8.314*298}{2*96500}*ln(1/0.014M)

E=-0.285V

Silver half-cell

Reduction reaction: Ag^+ + e^- \longrightarrow Ag

E=E^0 - \frac{R*T}{n*F}*ln(1/[Ag+])

E_{cell}=E_{red} - E_{ox}

E_{red}=1.12 V + (-0.855V)=0.835V

Assuming T=298 K / R=8.314 J/mol K / F=96500 C

0.835V=0.8V - \frac{8.314*298}{1*96500}*ln(1/[Ag+])

[Ag+]=0.26 M

3 0
3 years ago
The maximum energy of photo electrons (increases or decreases or remains constant) with increasing frequency and (increases or d
morpeh [17]

Answer:

Increases,  remain constant

Explanation:

In the light spectrum, the photons with a higher frequency (hence smaller wavelengths) have higher energy. The lower the energy the lower the frequency and longer the wavelengths. The intensity of light does not change the energy levels of these photons. The higher the intensity the higher the density of the photoelectrons.

4 0
3 years ago
Need help ASAP... The diagram shows a box in the periodic table.. what is the atomic number of the element??​
ad-work [718]
The atomic number is 15
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