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DerKrebs [107]
3 years ago
5

How many times thus the earth fit inside the sun​

Chemistry
1 answer:
vodka [1.7K]3 years ago
6 0
More than one million Earths could fit inside the Sun if it were hollow. The Sun has a radius of 696.340 km / 432.685 mi and a diameter of 1.39 million km / 864.000 mi.
You might be interested in
What is the molality of a solution in which 0.42 moles aluminum chloride has been dissolved in 4200 water ?
madreJ [45]

Answer:

0.1 M

<h3>Explanation:</h3>
  • Molarity refers to the concentration of a solution in moles per liter.
  • It is calculated by dividing the number of moles of solute by the volume of solvent;
  • Molarity = Moles of the solute ÷ Volume of the solvent

<u>In this case, we are given;</u>

  • Number of moles of the solute, NH₄Cl as 0.42 moles
  • Volume of the solvent, water as 4200 mL or 4.2 L

Therefore;

Molarity = 0.42 moles ÷ 4.2 L

            = 0.1 mol/L or 0.1 M

Thus, the molarity of the solution will be 0.1 M

7 0
3 years ago
Round off the following numbers to the number of significant figures (sf) indicated.
Flura [38]

Answer:

a. 7.52

b. 16.5

c. 85

d. 6.03

Explanation:

significant number exempts 0 as a number which explains the last one. The two significant numbers there are 6 and 3

6 0
3 years ago
Read 2 more answers
3,010,000 into scientific notation
skelet666 [1.2K]

Answer:

3.01 x 10 to the power of 6

Explanation:

Step 1

To find a, take the number and move a decimal place to the right one position.

Original Number: 3,010,000

New Number: 3.010000

Step 2

Now, to find b, count how many places to the right of the decimal.

3 0
3 years ago
Read 2 more answers
Identify the group of elements that does not readily combine with other elements.
7nadin3 [17]
Noble gases
also known as Inert gases
4 0
3 years ago
From the value Kf=1.2×109 for Ni(NH3)62+, calculate the concentration of NH3 required to just dissolve 0.016 mol of NiC2O4 (Ksp
Nina [5.8K]

<u>Answer:</u> The concentration of NH_3 required will be 0.285 M.

<u>Explanation:</u>

To calculate the molarity of NiC_2O_4, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

Moles of NiC_2O_4 = 0.016 moles

Volume of solution = 1 L

Putting values in above equation, we get:

\text{Molarity of }NiC_2O_4=\frac{0.016mol}{1L}=0.016M

For the given chemical equations:

NiC_2O_4(s)\rightleftharpoons Ni^{2+}(aq.)+C_2O_4^{2-}(aq.);K_{sp}=4.0\times 10^{-10}

Ni^{2+}(aq.)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K_f=1.2\times 10^9

Net equation: NiC_2O_4(s)+6NH_3(aq.)\rightleftharpoons [Ni(NH_3)_6]^{2+}+C_2O_4^{2-}(aq.);K=?

To calculate the equilibrium constant, K for above equation, we get:

K=K_{sp}\times K_f\\K=(4.0\times 10^{-10})\times (1.2\times 10^9)=0.48

The expression for equilibrium constant of above equation is:

K=\frac{[C_2O_4^{2-}][[Ni(NH_3)_6]^{2+}]}{[NiC_2O_4][NH_3]^6}

As, NiC_2O_4 is a solid, so its activity is taken as 1 and so for C_2O_4^{2-}

We are given:

[[Ni(NH_3)_6]^{2+}]=0.016M

Putting values in above equations, we get:

0.48=\frac{0.016}{[NH_3]^6}}

[NH_3]=0.285M

Hence, the concentration of NH_3 required will be 0.285 M.

7 0
3 years ago
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